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tekilochka
16 days ago
15

3x−8≤23 OR −4x+26≥6 solve for x

Mathematics
2 answers:
Zina [3.9K]16 days ago
6 0

Answer:

x ≤ 31/3

The solution to the first inequality, 3x - 8 ≤ 23, resolves to x ≤ 31/3

The solution for the second inequality, -4x + 26 ≥ 6, simplifies to x ≤ 5

The overarching solution derived from both inequalities is x ≤ 31/3

Leona [4.1K]16 days ago
5 0

Response:

x  ≤ 31/3

Detailed explanation:

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The quotient of 9 3/4 and 5/8​
AnnZ [3877]

Answer:

15.6

Step-by-step explanation:

  1. 9\frac{3}{4} = \frac{39}{4}
  2. Insert 39/4: 39/4 ÷ 5/8
  3. 39/4 ÷ 5/8 = 39/4 × 8/5
  4. 39/4 × 8/5 = 312/20
  5. \frac{312}{20} = 15.6

I hope this information is helpful!

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Chuck has a gross pay of $815.70. By how much will Chuck’s gross pay be reduced if he has the following items withheld?
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Chuck's gross pay will decrease by $129.04.
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What is the relative frequency of the revenue earned by B&B Motors from sales of mini trucks compared to the total sales rev
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Answer: 0.46

Step-by-step explanation:

B&B Motors' mini trucks yield 0.59; all four companies combined yield 0.39; mini trucks yield 0.13. Hence, 0.59 - 0.13 equals 0.46.

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An experiment consists of determining the speed of automobiles on a highway using a radar equipment. The random variable in this
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Answer:

the speed value produced by the radar equipment.

Step-by-step explanation:

In an experiment, a random variable is typically referred to as a dependent variable. In this context, the random variable pertains to the speed value produced by the radar equipment. This value is reliant on the actual speeds of the cars that go past the equipment. A higher speed results in a greater value shown by the radar. Thus, it relies entirely on the automobiles.

8 0
5 days ago
Find the dimensions of the closed rectangular box with maximum volume that can be inscribed in the unit sphere.
Inessa [3907]

Answer:

Wyjaśnienie krok po kroku:

Załóżmy, że prostokąt ma wierzchołki (x,y,z) w dodatnim oktancie.  Prostokątny pudełko musi być symetryczne względem wszystkich trzech osi.

Wtedy jego boki to

2x,2y,2z

Objętość = 8xyz

Maksymalizuj objętość przy założeniu

x^2+y^2+z^2 =1

tj. g(x,y,z) = x^2+y^2+z^2 -1=0

Użyj mnożników Lagrange'a, mamy

∇f(x,y,z)=λ∇g(x,y,z)przy maksimum

∇f(x,y,z)=λ∇g(x,y,z) =(8yz,8xz,8xy)\\∇g(x,y,z)=(2x,2y,2z)

8yz=2λx8xz=2λy8xy=2λz

Dzieląc otrzymujemy

\frac{y}{x} =\frac{x}{y} \\x^2=y^2

Podobnie y^2=z^2

Zatem otrzymujemy 3x^2 =1\\x = \frac{1}{\sqrt{3} }

Stąd wymiary to

(2x,2y,2z)

<pzatem wymiary="" to="">

\frac{2}{\sqrt{3} },\frac{2}{\sqrt{3} },\frac{2}{\sqrt{3} } )

</pzatem>
3 0
1 day ago
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