Explain why the cost of ownership may be lower with a cloud database than with a traditional, company database.

Response:

The correct option is "Option a".

Analysis:

A negative score can be harmful. A score below zero indicates that the sequences leading up to this point are uncorrelated, effectively voiding their influence on prior alignment. Thus, alignment can still be pursued at any position later in the calculation. The other options can be elaborated on:[

• In option b, the score could potentially be negative, hence its value cannot be fixed.
• Option c states that some value is required in the first row and column, ruling it out as correct.
• As for option d, it suggests starting with a lower score and concluding with a higher one, which is also incorrect.

Answer:

Below is the month_days function:

def month_days(month, days):

 print (month +" has " + str(days) + " days.")

You can invoke this function with arguments like:

month_days ("June", 30)

month_days("July", 31)

The function can also be restructured as follows:

def month_days(month, days):

 return (month +" has " + str(days) + " days.")

To view the output, call the function along with print like this:

print(month_days ("June", 30))

print(month_days("July", 31))

Explanation:

The defined month_days function takes two parameters: the month name and the number of days in that month. It has a return statement return (month +" has " + str(days) + " days.") which combines the month name held in the variable month with the word "has" and then the number of days stored in days followed by the term days.

For instance, if "June" is passed in as month and 30 as days, the output will be:

June has 30 days.

This program can also be constructed using an f-string for better formatting in the month_days function:

def month_days(month, days):

   output = f"{month} has {days} days."

   return (output)

To see the output, invoke the function with print:

print (month_days("June", 30))

print (month_days("July", 31))

The f-string starts with 'f' and includes the parameters month and days within curly braces. The variables month and days are substituted with their respective values when the function is called.

Screenshot of the program and its output is attached.

Response:

C++ code provided below with suitable annotations

Clarification:

pattern.cpp

#include<iostream>

using namespace std;

void printCross(int n)

{

int i,j,k;

if(n%2) //odd number of lines

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==i || j==(n-i+1))

cout<<j;

else

cout<<" ";

}

cout<<"\n";

}

}

else //even number of lines

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==i || j==(n-i+1))

{

cout<<" "<<j<<" ";

}

else

cout<<" ";

}

cout<<"\n";

}

}

void printForwardSlash(int n)

{

if(n%2)

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==n-i+1)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

else

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==(n-i+1))

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

}

void printBackwardSlash(int n)

{

if(n%2) // odd number of lines

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==i)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

else //even number of lines

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==i)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

}

int main()

{

int num;

char ch;

cout<<"Create a numberes shape that can be sized."<<endl;

cout<<"Input an integer [1,50] and a character [x,b,f]."<<endl;

cin>>num>>ch;

if(ch=='x' || ch=='X')

printCross(num);

else if(ch=='f' || ch=='F')

printForwardSlash(num);

else if(ch=='b' || ch=='B')

printBackwardSlash(num);

else

cout<<"\nWrong input"<<endl;

return 0;

}

Question:

The function is_positive should yield True if the supplied number is positive; otherwise, it gives None. Can you fill in the blanks accordingly?

def is_positive(number):

       if  _____ :

           return _____

Answer:

def is_positive(number):

   if (number > 0):

       return True

  else:

       return "None"

---------------------------------------------------------------------------------

Code Test and Sample Output:

print(is_positive(6))

>> True

print(is_positive(-7))

>> None

----------------------------------------------------------------------------------

Explanation:

This segment of code is composed in Python.

To explain it further, let's break down the content of each line;

Line 1: Creates a function identified as is_positive which takes in a variable number.i.e

def is_positive(number):

Line 2: Evaluates if the given number is positive; a number qualifies as positive if it exceeds zero. i.e

if (number > 0):

Line 3: Produces a boolean result of True when the input number is positive. i.e

return True

Line 4: Initiates the else block to be executed in case the input number isn’t positive. i.e

else:

Line 5: Returns the string "None" when the number is not positive. i.e

return "None"

When combined, this results in;

===============================

def is_positive(number):

   if (number > 0):

       return True

   else:

       return "None"

================================

An instance test for the code provided an argument of 6 and -7, resulting in True and None respectively. i.e

print(is_positive(6))   = True

print(is_positive(-7))  = None