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Simora
1 month ago
12

Until 2015, each new Roblox user automatically had one friend. What was he called?

Computers and Technology
2 answers:
amid [867]1 month ago
6 0

Prior to 2015, every new Roblox participant was assigned a friend known as Builderman.

Builderman served as the automatic friend for all users before 2015.

Further Explanation

This Builderman greeted each incoming Roblox user, sending them a welcoming message, and followed every user until the service was discontinued in 2014. The purpose of Builderman was to orientate new users to the Roblox gaming experience.

Roblox functions as an online game platform where users can also create their own games. Roblox provides users with the ability to design and access a variety of games developed by other users.

Roblox features countless user-created games and virtual environments spanning different genres, including classic racing, obstacle courses, and more.

With millions of users globally, Roblox boasts over 100 million active users each month. Additionally, it allows users to create virtual items to sell, meaning users can produce virtual goods for sale to one another.

Roblox was established by David Baszucki and Erik Cassel and launched on September 1, 2006. It supports both single-player and multiplayer modes.

LEARN MORE:

  • Until 2015, what was the name of the automatic friend assigned to each new Roblox user?
  • What is the name of the programming language used in Roblox?

KEYWORDS:

  • roblox
  • builderman
  • friend
  • message
  • automatically
  • david baszucki
  • erik cassel
Natasha_Volkova [941]1 month ago
4 0

I hope this clarifies things. The answer is likely either Hackers or Builderman, but more likely Builderman!

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ivann1987 [982]

Answer:

I am crafting a Python function:

def angry_file_finder(filename): #function definition, this function takes the file name as input

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for line in lines: #iterates through every line of the file

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print(angry_file_finder("file.txt")) invokes the angry_file_finder function by supplying a text file name to it

Explanation:

The angry_file_finder function accepts a filename as its parameter. It opens this file in read mode utilizing the open() method with "r". Then it reads every line using the readline() function. The loop checks each line for the presence of the "!" character. If any line in the file lacks the "!" character, the function returns false; otherwise, it returns true.

There is a more efficient way to write this function without using the readlines() method.

def angry_file_finder(filename):

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print(angry_file_finder("file.txt"))

The revised method opens the file in reading mode and directly uses a for-loop to traverse through each line to search for the "!" character. In the for-loop, the condition checks if "!" is absent from any line in the text file. If it is missing, the function returns False; otherwise, it returns True. This approach is more efficient for locating a character in a file.

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Answer:

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In this expression, we observe that the '2' in the hundred's place must be converted to '0' while carrying over '1' to the thousand's position, leading to;

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This shows that;

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Next, we convert the outcome of squaring the base 2 number, 11001₂, into base 10 through the following method;

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7 0
1 month ago
Input a number [1-50] representing the size of the shape and then a character [x,b,f] which represents the shape i.e. x->cros
Harlamova29_29 [950]

Response:

C++ code provided below with suitable annotations

Clarification:

pattern.cpp

#include<iostream>

using namespace std;

void printCross(int n)

{

int i,j,k;

if(n%2) //odd number of lines

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==i || j==(n-i+1))

cout<<j;

else

cout<<" ";

}

cout<<"\n";

}

}

else //even number of lines

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==i || j==(n-i+1))

{

cout<<" "<<j<<" ";

}

else

cout<<" ";

}

cout<<"\n";

}

}

void printForwardSlash(int n)

{

if(n%2)

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==n-i+1)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

else

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==(n-i+1))

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

}

void printBackwardSlash(int n)

{

if(n%2) // odd number of lines

{

for(int i=n;i>=1;i--)

{

for(int j=n;j>=1;j--)

{

if(j==i)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

else //even number of lines

{

for(int i=1;i<=n;i++)

{

for(int j=1;j<=n;j++)

{

if(j==i)

{

cout<<j;

}

else

cout<<" ";

}

cout<<"\n";

}

}

}

int main()

{

int num;

char ch;

cout<<"Create a numberes shape that can be sized."<<endl;

cout<<"Input an integer [1,50] and a character [x,b,f]."<<endl;

cin>>num>>ch;

if(ch=='x' || ch=='X')

printCross(num);

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printForwardSlash(num);

else if(ch=='b' || ch=='B')

printBackwardSlash(num);

else

cout<<"\nWrong input"<<endl;

return 0;

}

4 0
23 days ago
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