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mihalych1998
17 days ago
14

Anika buys a pair of shin guards for $8.58 and several pairs of soccer socks for $4.29 per pair. If she spends $25.74 before tax

es, how many pairs of socks does Anika buy?
Mathematics
1 answer:
Svet_ta [6.6K]17 days ago
5 0
Anika purchased 4 pairs of socks.
You might be interested in
The present age of Alex is ‘y’ years. Answer the following
PIT_PIT [6417]

Answer:

(a) What will his age be after 5 years?

"5 + y" years old

(b) What was his age 6 years ago?

"y - 6" years old

(c) If his grandfather’s age is five times his, how old is his grandfather?

"5y" years old

(d) His father is 6 years older than three times his age. How old is his father?

"6 + 3y" years old

Note: Disregard the quotation marks, ""

5 0
10 days ago
Read 2 more answers
In triangle RST, m∠R > m∠S + m∠T. Which must be true of triangle RST? Check all that apply.
zzz [6262]

Answer:

∠ R > 90°

\angle s + \angle T < \angle 90

\angle R > \angle T

\angle R > \angle S    

Explicación paso a paso:

Dado que en el triángulo RST

\angle R> (\angle s +\angle T)

Ahora, según la condición, un ángulo es mayor que la suma de los otros dos ángulos.

En un triángulo, la suma de los tres ángulos es 180°

Por lo tanto, si un ángulo mide  90°, la suma de los otros dos debe ser igual a 90°

Y si uno de los ángulos es de 90°, solo los otros dos pueden ser de 45° cada uno.

Aquí suponiendo que el ángulo s = ángulo T = 30°, entonces con esta condición el ángulo r sería de 120°, que es mayor que 90°.

De lo anterior, se concluye que

Para, \angle R> (\angle s +\angle T)

∵ ∠ R = 120°, por lo tanto es mayor que 90°.

Es decir, ∠ R > 90°

\angle s + \angle T < \angle 90

\angle R > \angle T

\angle R > \angle S   Respuesta

9 0
22 days ago
Read 2 more answers
In triangle JKL, sin(b°) = three fifths and cos(b°) = four fifths. If triangle JKL is dilated by a scale factor of 2, what is ta
Inessa [6008]

Answer:

Tan(b°) = 3/4, which is equivalent to three fourths (C).

Step-by-step explanation:

Triangle JKL is a right triangle with angle K being the right angle and angle L equal to b°.

We will employ SOHCAHTOA principles from trigonometry to calculate the sides' values.

For triangle ∆JKL:

Sin(b°) = opposite/hypotenuse

Sin(b°) = 3/5

Cos(b°) = adjacent/hypotenuse

Cos(b°) = 4/5

Tan(b°) = 3/4.

From the earlier information, we have the values for each side of triangle ∆JKL.

Please refer to the attached diagram for the triangle (1).

Triangle ∆JKL is scaled with a factor of 2.

This implies multiplying each side of ∆JKL by 2, resulting in:

Opposite side = 2(3) = 6

Adjacent side = 2(4) = 8

Hypotenuse = 2(5) = 10.

To find tan(b°) for the new triangle, we use the tangent ratio:

Tan(b°) = opposite/adjacent.

Tan(b°) = 6/8.

Tan(b°) = 3/4.

Find the diagram for the new triangle included (2).

Diagram 3 provides a depiction of both triangles.

As shown, the angle remains unchanged when a triangle is scaled by a factor.

Thus, we conclude that tan(b°) = three fourths (C).

6 0
9 days ago
A local pizzeria offers 15 toppings for their pizzas and you can choose any 3 of them for one fixed price. How many different ty
Svet_ta [6680]

Answer:

It could either be 455 or 680, based on assumptions.

Step-by-step explanation:

Assuming the three choices are distinct, we can calculate...

  15C3 = 15·14·13/(3·2·1) = 35·13 = 455

ways to create the pizza.

___

In the case where two or more of the toppings may be identical, this would lead to...

  2(15C2) + 15C1 = 2·105 + 15 = 225

additional combinations, resulting in a grand total of...

  455 + 225 = 680

unique pizza varieties.

__

There is a multiplication factor of 2 for the two-topping selections, since it allows for variations like double anchovies and tomatoes or double tomatoes and anchovies when the topping choices are anchovies and tomatoes.

_____

nCk = n!/(k!(n-k)!)

6 0
12 days ago
Alice and Briana each participate in a 5 kilometer race. Alice's distance covered, in kilometers, after t minutes can be modeled
PIT_PIT [6417]

Answer:

a. Alice

b. Briana

c. 0.51 minutes

Step-by-step explanation:

a. Alice's formula is applicable for any t > 0 minutes, while Briana’s is only applicable when

2t - 1 > 0

2t > 1

t > 1/2 minutes

b. They complete the race when their total distance equals 5 kilometers. For Alice:

t/4 = 5

t = 20 minutes

For Briana:

√(2t - 1) = 5

2t - 1 = 25

2t = 26

t = 13 minutes

c. They reach the same point when they have traveled the same distance, expressed as:

t/4 = √(2t - 1)

(t/4)² = 2t - 1

t²/16 = 2t - 1

t² = 16(2t - 1)

t² = 32t - 16

t² - 32t + 16 = 0

Using the quadratic formula:

t = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}

t = \frac{32 \pm \sqrt{-32^2 - 4(1)(16)}}{2(1)}

t = \frac{32 \pm 30.98}{2}

t_1 = \frac{32 + 30.98}{2}

t_1 = 31.49

t_2 = \frac{32 - 30.98}{2}

t_2 = 0.51

Only the second solution fits this scenario because the race concluded before they took 31.49 minutes.

4 0
15 days ago
Read 2 more answers
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