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mars1129
3 months ago
14

Matt suffered slight burns in an accident. When the skin burns, it loses some of its functions. First-degree burns affect the to

p layer of skin. What effect will first-degree burns most likely have on the upper layer of the skin? Matt loses his sensation of pain. The skin will have no sensation at all. Matt will be more prone to infections. The sebaceous glands will stop moisturizing the skin. The skin loses its elasticity.
Biology
2 answers:
s2008m [2.3K]3 months ago
8 0
When first-degree burns occur, the skin loses its elasticity because this type of burn primarily impacts only the outer layer, the epidermis, where nerves and glands are absent.
Tresset [2.2K]3 months ago
5 0

The skin experiences a loss of elasticity.

First-degree burns target just the topmost epidermal layer of the skin. Depending on the heat source's intensity, these burns can be painful. Healing from a first-degree burn may take between 5 to 10 days, influenced by how extensive the burn area is. Such burns are mild and do not penetrate deeper layers, meaning nerve endings remain safe, and infection risks are minimal. The skin can still sweat as the epidermis is affected, while the sebaceous glands are located in the deeper dermal layer. The new epidermal layer formed post-injury will be less elastic than healthy skin, limiting touch sensation.

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A person who is homozygous for the x chromosome is
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An individual who possesses two identical X chromosomes is female.
Since women have a pair of X chromosomes, they are considered homozygous for the X chromosome - the term homozygous refers to having 'two chromosomes of the same type.' In contrast, men typically have different chromosome types - XY.

7 0
2 months ago
Using the sliding flament theory, explain (or draw) the process of sarcomere shortening. Start from the point where calcium woul
enyata [2506]

Answer:

  1. Calcium attaches to troponin C
  2. Troponin T shifts tropomyosin to reveal the binding sites
  3. Myosin heads connect to actin, forming cross-bridges
  4. ATP is converted to ADP and inorganic phosphate and releases energy
  5. This energy drives the sliding of myofilaments, resulting in a power stroke
  6. ADP detaches and a fresh ATP binds to the myosin heads, breaking the bond with the actin filament
  7. ATP is then split into ADP and phosphate, storing energy in the myosin heads, thus beginning another cycle
  8. Z-bands are drawn together, which shortens the sarcomere and the I-band, leading to muscle contraction.

Explanation:  

At rest, tropomyosin blocks the attraction between actin and myosin filaments. Contraction starts when an action potential depolarizes the interior of the muscle fiber. Calcium channels in the T tubules open, leading to the release of calcium into the sarcolemma. At this moment, tropomyosin obstructs the myosin binding sites on actin. Upon binding of calcium to troponin C, troponin T modifies the position of tropomyosin, exposing the binding sites. Myosin heads attach to the exposed actin sites forming cross-bridges, while ATP is converted into ADP and inorganic phosphate, which is then released. The sliding of myofilaments is driven by the chemical energy stored in myosin heads, resulting in a power stroke. The power stroke starts as the myosin cross-bridge binds to actin. During the slide, ADP is released. A new ATP connects to myosin heads, terminating the bond with the actin filament.  Then ATP is split into ADP and phosphate, and the energy generated is stored in the myosin heads, which initiates a new cycle of binding to actin. In the end, Z-bands pull together, which shortens the sarcomere and the I-band, causing muscle fiber contracture.

4 0
3 months ago
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