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Nadusha1986
1 month ago
15

A camera is selling for $7.50 off the regular price. It was marked down 15%. A student used the equation:

Mathematics
2 answers:
babunello [11.8K]1 month ago
8 0

Answer:

A camera is discounted by $7.50 off its original price and had a 15% markdown.

Let the original price be represented as x

The solution proceeds as follows:

x-0.15x=7.50

=> 0.85x=7.50

=> x = 8.82

The actual original price comes to $8.82.

A student used the equation:

15(7.5) = Original price

and calculated the camera's original price to be $112.50.

This calculation was incorrect. The student mistakenly calculated 15% of the selling price instead of the original price.

He should have calculated 15% of the original price to equal the selling price.

lawyer [12.5K]1 month ago
4 0

Answer:

The student should have divided the amount after the discount by the percentage expressed as a decimal.

Step-by-step explanation:

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Answer:

Answer and Explanation:

We have:

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The expected value of the sampling distribution equals the population mean,

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The sampling distribution of

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(

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z

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6 0
1 month ago
Find the values of x1 and x2 where the following two constraints intersect.
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Step-by-step explanation:

Greetings!

As illustrated in the diagram, the point you seek is where the two lines intersect.

This intersection point is found by solving the system of linear equations (both equations must be satisfied by the point):

9x_1 +7x_2=57\\4x_1 + 6x_2 = 13

You can approach solving it using the substitution method:

\text{solve for x1 in the first equation:}\\x_1 = \frac{1}{9}(57 - 7x_2)

Then substitute x1 into equation 2 to resolve x2:

\frac{4}{9}(57-7x_2) + 6x_2 = 13\\\text{doing the algebra you get:}\\x_2 = \frac{-111}{26}

After which, utilize the x2 value to establish x1:

x_1 = \frac{1}{9}(57 - 7x_2)= \frac{1}{9}(57 + 7*\frac{111}{26}) = 251/26\\

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28 days ago
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Therefore, \frac{2}{6} equals \frac{3}{9}.

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