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LiRa
2 months ago
6

Write a program that allows the user to navigate the lines of text in a file. The program should prompt the user for a filename

and input the lines of text into a list. The program then enters a loop in which it prints the number of lines in the file and prompts the user for a line number. Actual line numbers range from 1 to the number of lines in the file. If the input is 0, the program quits. Otherwise, the program prints the line associated with that number

Computers and Technology
2 answers:
amid [951]2 months ago
7 0

This code is in Python. I'm not certain what programming language you need.

Refer to the image:

Harlamova29_29 [1K]2 months ago
7 0

Answer:

#section 1

filename = input('Enter file name: ')

with open(filename,'r') as file:

   

   lines = []

   for line in file:

         lines.append(line.strip())

print('Total lines in the file:', len(lines))

#section 2

while True:

   line_number = int(input('Enter line number: '))

   if line_number == 0:

       break

   else:

       index = line_number - 1

       print(lines[index])

Explanation:

The programming language utilized is Python

# section 1

In this part, the program prompts the user for the file's name. It opens the file using a WITH statement, ensuring that it closes automatically when done.

An empty list is created to store the lines from the file.

A FOR loop is implemented to read through the file, adding each line to the list. The .strip() function removes any unwanted characters such as \t and \n from the text.

At the end of this section, the total line count is displayed using the len() function.

#section 2

<pIn this section, a WHILE loop is initiated to continue running until the user enters 0. The loop requests a line number from the user and then outputs that line's content to the screen.

I have included the result as an image.

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The provided explanation, including the step-by-step code, is as follows: We can approach this issue employing the if elif else model. def main(): # prompts the user to input an integer between 1 to 10 num = int(input('Enter a number in the range of 1 to 10:\n')) # utilizing if elif to display the roman numeral from 1 to 10 if num == 1: print('Roman Numeral for 1 is I') elif num == 2: print('Roman Numeral for 2 is II') elif num == 3: print('Roman Numeral for 3 is III') elif num == 4: print('Roman Numeral for 4 is IV') elif num == 5: print('Roman Numeral for 5 is V') elif num == 6: print('Roman Numeral for 6 is VI') elif num == 7: print('Roman Numeral for 7 is VII') elif num == 8: print('Roman Numeral for 8 is VIII') elif num == 9: print('Roman Numeral for 9 is IX') elif num == 10: print('Roman Numeral for 10 is X') # else to show error message for numbers outside the specified range else: print('Error! Wrong Input') # invoking the main function main() Output: Enter a number in the range of 1 to 10: 6 Roman Numeral for 6 is VI Enter a number in the range of 1 to 10: 15 Error! Wrong Input.
6 0
1 month ago
Define a method calcPyramidVolume with double data type parameters baseLength, baseWidth, and pyramidHeight, that returns as a d
Rzqust [1037]

Answer:

The C++ method is defined as follows:

double calcPyramidVolume(double baseLength, double baseWidth, double pyramidHeight){

   double baseArea = calcBaseArea(baseLength, baseWidth);

   double volume = baseArea * pyramidHeight;

   return volume;    

}

Explanation:

This establishes the calcPyramidVolume method

double calcPyramidVolume(double baseLength, double baseWidth, double pyramidHeight){

This invokes the calcBaseArea method to derive the base area of the pyramid

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This calculates the volume based on the base area

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This yields the calculated volume

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Refer to the attached document for the complete program that includes all required methods.

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2 months ago
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Answer:

=IF(D15<1500, "Discontinue", "No Change")

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Your condition is placed before the first comma, which is D15 < 1500.

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Answer:

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3 0
2 months ago
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amid [951]

Options :

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Answer:

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