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Ivenika
1 month ago
10

On a given day, the proportion of workers from Company B who purchase a coffee from the company cafeteria is 0.62 and the propor

tion of workers from Company C who purchase a coffee from the company cafeteria is 0.71. A random sample of40 workers was selected from Company B and another random sample of 40 workers was selected from Company C. The proportion of workers from Company B who purchased coffee was pˆB=0.70 and the proportion of workers from Company C who purchased coffee was pˆC=0.75.
What is the correct unit of measure for the mean of the sampling distribution of pˆB−pˆC ?
Advanced Placement (AP)
1 answer:
Anna [191]1 month ago
5 0

Answer:

The mean of a sampling distribution does not have units.

Explanation:

Given that:

P(B) = 0.62

P(C) = 0.71

pˆB = 0.70

pˆC = 0.75

The expression: pˆB−pˆC

Denotes the difference in means of the sample distribution:

The proportions pˆB = 0.70 and pˆC = 0.75 are determined by (number of employees who bought coffee / total number of employees). The aforementioned ratio will have no units due to the division.

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