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IRISSAK
1 month ago
9

An infinitely long cylinder of radius R has linear charge density λ. The potential on the surface of the cylinder is V0, and the

electric field outside the cylinder is Er=λ2πϵ0r. Part A Find the potential relative to the surface at a point that is distance r from the axis, assuming r>R. Express your answer in terms of the variables λ, r, R, V0, and appropriate constants. Vr = nothing

Physics
1 answer:
kicyunya [3.2K]1 month ago
5 0

Answer:

V = V_0 - (lamda)/(2pi(epsilon_0))*ln(R/r)

Explanation:

The complete solution is provided in the attachment.

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A particular brand of gasoline has a density of 0.737 g/mLg/mL at 25 ∘C∘C. How many grams of this gasoline would fill a 14.9 gal
Yuliya22 [3333]

Answer:

The answer to your inquiry is Mass = 41230.7 g or 41.23 kg.

Explanation:

Data

Density = 0.737 g/ml

Mass = ?

Volume = 14.9 gal

1 gal = 3.78 l

Process

1.- Convert gallons to liters

1 gal ---------------- 3.78 l

14.9 gal ------------- x

x = 56.44 l

2.- Convert liters to milliliters

1 l ------------------- 1000 ml

56.44 l --------------- x

x = (56.44 x 1000) / 1

x = 56444 ml

3.- Calculate the mass

Formula

Density = \frac{mass}{volume}

Solving for mass

Mass = density x volume

Substituting values

Mass = 0.737 x 56444

Result

Mass = 41230.7 g or 41.23 kg.

3 0
2 months ago
Which contributions did Galileo make to the model of the solar system? Select two options.a mathematical model for the orbits of
Sav [3153]
Galileo's contributions to the solar system model include: Data indicating that planets reflect sunlight like the Moon, and his observations of Jupiter's moons orbiting the gas giant. With the assistance of an early telescope that he constructed, Galileo made these two significant discoveries.
7 0
1 month ago
A 20.00-kg lead sphere is hanging from a hook by a thin wire 2.80 m long and is free to swing in a complete circle. Suddenly it
Keith_Richards [3271]
Objects in vertical motion are an illustration of non-uniform motion. At the peak of the circle, centripetal force is balanced by the object's weight. Therefore, the minimum speed required at this top point is given by v = \sqrt{rg} = \sqrt{2.80 \times 9.8} = 5.23 m/s. As the sphere descends from the top to the bottom of the circle, according to the law of conservation of energy, potential energy can be expressed as

P.E_{highest} = mgh

, where h signifies the diameter of the circle (2r). Hence, the expression will be written as P.E_{highest} = mg(2r)

where u is the velocity at the lowest point. Consequently, the modified equation is

= \sqrt{v^{2} + 4gr}

= \sqrt{(5.23)^{2} + (4 \times 9.8 \times 2.80)}

= 11.71 m/s. The collision of the dart with the bullet is an inelastic one. According to the conservation of momentum: v = \frac{(m_{1} + m_{2})u}{m_{2}}

= \frac{(20 + 5) \times 11.71}{5}

= \frac{292.75}{5}

= 58.55 m/s. Thus, the dart's minimum initial speed for the combined system to complete a circular loop post-collision is 58.55 m/s.

3 0
20 days ago
The acceleration of segment D is m/s2. Rank segments A, B , C from least accelerations to greatest acceleration. Least
Ostrovityanka [3204]

Answer:

D, C, B, A

Explanation:

The derivative from a velocity-time graph provides the acceleration value.

Segment A

\frac{dy}{dx} = \frac{15m/s}{1s} = 15m/s^2

Segment B

\frac{dy}{dx} = \frac{5m/s}{1s} = 5m/s^2

Segment C

\frac{dy}{dx} = \frac{0m/s}{2s} = 0m/s^2

Segment D

\frac{dy}{dx} = \frac{-20m/s}{1s} = -20m/s^2

Sorted from the lowest to the highest acceleration:

D, C, B, A

8 0
1 month ago
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An object has kinetic energy of 324 J. If it’s speed is 9m/s, what is it’s mass?
ValentinkaMS [3465]
It is 8 kilograms. I had to provide more text, so here it is.
6 0
16 days ago
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