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Hitman42
2 months ago
4

In chickens, the allele for a pea comb (A) is dominant to the allele for a single comb (a).

Biology
2 answers:
-BARSIC- [2.5K]2 months ago
5 0

Response: The likelihood that the offspring will exhibit a single comb is 25%

Clarification: When a mother with the genotype Aa and a father also with the genotype Aa are crossed, they can yield four offspring: 1AA, 2Aa, and 1aa, which can be represented as Aa x Aa = AA, Aa, Aa, and aa.

Offspring with genotypes AS and Aa will display a pea comb, while those with the genotype aa will show a single comb. Consequently, one out of the four offspring will have a single comb.

Thus, the likelihood of producing an offspring with a single comb is calculated as 1/4 x 100 = 25%

Punnet square

- A a

A AA AA

a Aa aa

-BARSIC- [2.5K]2 months ago
3 0

Answer:

In chickens, the allele for a pea comb (A) is dominant over the allele for a single comb (a). A mother with genotype Aa and a father with genotype Aa produce progeny. What is the probability that one of the offspring will exhibit a single comb?

A= Pea comb

a= single comb

Cross Aa x Aa results in: AA, Aa, Aa, and aa

The likelihood of producing offspring with a single comb is 25%, while 75% will have a pea comb, consisting of two homozygous (Aa dominant pea comb and aa recessive single comb) and two heterozygous (Aa and Aa)

Explanation:

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