The y-intercept is now 12.5, and the slope has increased to 0.5625. After the policy adjustment, an additional $5 was included, followed by multiplying the total amount by 1.25.
In this problem the number we are working with is:
105,159
By definition we note:
thousand place: a five-digit quantity greater than zero.
Moreover, the rounding rule is:
if the digit being removed is 5 or more, increase the kept digit by one.
Therefore, rounding to the nearest ten thousand yields:
105,159 = 110,000
Answer:
105,159 rounded to the nearest ten thousand is:
105,159 = 110,000
Let
denote the length of the pond and <span> signify its width. It's recognized that the pond's volume equals the area of its base multiplied by its depth. In this case, the base area can be computed as volume divided by depth, equating to 72000 in³ divided by 24 in, resulting in an area of 3000 in². Given that the area is expressed as x multiplied by y, we come to equation 1, 3000 = x * y. If we have x = 2y, we substitute this into equation 1, leading to 3000 = (2y) * y, simplifying to 2y² = 3000 and consequently y² = 1500, giving y = 38.7 in. Thus, x = 2y yields x = 2 * 38.7 = 77.4 in. The conclusion is that the pond's length is 77.4 in while its width is 38.7 in.
</span>
To calculate the mean absolute deviation of
1,2,3,4,5,6,7
, we start by finding the mean;
(1+2+3+4+5+6+7) =28/7
= 4
. Next, we determine the absolute differences of each data point from the mean (x-μ)
= -3,-2,-1,0,1,2,3
. The absolute values are 3,2,1,0,1,2,3
. Now we compute the mean of these absolute differences,
3+2+1+0+1+2+3 = 12
= 12/7
= 1.7143
. Thus, the mean is 4, and the Mean absolute deviation comes out to be 1.7143
Four statements:
1) Start by dividing the x-axis into equal segments.
2) n = 212/5 = 42.4.
3) Each segment along the x-axis represents 42.4. This means you can plot the point -212 at x = -5
4) The y-axis can keep its magnitude and you can plot the coordinate of -4 at y = -4
