What is the range of the function represented by the graph?

To tackle this issue, we need to clarify what each variable stands for. Here, n indicates the number of pencil packages purchased by Yolanda, while m represents the number of paper pads she buys. We calculate the total cost by multiplying these variables by their individual prices, which helps us determine the expense for both pencil packages and pads of paper.

The expression "1.4n" indicates the overall cost for n pencil packages.

On the other hand, "1.2m" signifies the complete expense for m pads of paper.

As we sum these two expressions, the resulting total reflects the overall expenditure for both items.

The equation "1.4n + 1.2m" summarizes this calculation.

I hope this provides clarity!

762,508 expressed in expanded form with exponents is:

Solution:

We need to write 762,508 using expanded notation with exponents.

Expanded form indicates how to represent numbers to highlight the individual digit values.

Displaying 762508 in Expanded format

Let's determine the positional values of each digit:

The concept of place value signifies the worth assigned to each digit based on its location.

For 7, the place value is 700,000

In 762508, the digit 7 is located in the hundred-thousands position.

For 6, the place value is 60,000

In 762508, the digit 6 occupies the ten-thousands position.

For 2, the place value is 2,000

In 762508, 2 is in the thousands position.

For 5, the place value is 500

In 762508, 5 is placed in the hundreds position.

For 0, the place value is 0 x 10 = 0

In 762508, 0 is found in the tens position.

For 8, the place value is 8

In 762508, 8 is positioned in the units place.

Thus, the expanded form is:

700,000 + 60,000 + 2,000 + 500 + 0 + 8

Expressed with exponents, it can be written as:

Got it!
There are 2π radians in a complete circle.

Now, let's calculate the circumference.
5/2π = 60/circumference.
Next, solve for the circumference.
By multiplying both sides by 2π, we have: 5 * circumference = 120π.
Now divide both sides by 5, and we find: circumference = 24π.

Using the formula c = 2πr,
we set 24π = 2πr.
Dividing both sides by 2π gives us r = 12. Thus, the radius measures 12cm.

Answer:

B

Step-by-step explanation:

If two quantities have a direct variation, their graph will originate from the point of intersection at the origin.

Among all graphs, only Nikiya's intersects the origin, thus the answer is B.

Answer:

Step-by-step explanation:

<pGreetings!

a. The variable X represents the height of a Goomba, which follows a normal distribution with a mean of μ= 12 inches and a standard deviation of δ= 6 inches.

To find the probability that a Goomba picked at random has a height between 13 and 15 inches, you express it as:

P(13≤X≤15)

Considering that standard normal probability tables provide cumulative values, you can express this range as the cumulative probability up to 15 minus the cumulative probability up to 13. You'll first need to standardize these variable heights to obtain corresponding Z values:

P(X≤15) - P(X≤13)

P(Z≤(15-12)/6) - P(Z≤(13-12)/6)

P(Z≤0.33) - P(Z≤0.17)= 0.62930 - 0.56749= 0.06181

b. Now we have Y as the variable indicating the height of a Koopa Troopa. This variable also follows a normal distribution, with a mean μ= 15 inches and a standard deviation δ=3 inches.

The query concerns the probability that a Koopa Troopa stands taller than 75% of Goombas.

First step:

You need to determine the height of a randomly chosen Koopa Troopa that exceeds 75% of the Goomba population.

This entails determining the value of X corresponding to the limit below which 75% of the population falls, denoted by:

P(X ≤ b)= 0.75

Step 2:

Search the standard normal distribution for the Z value that has 0.75 beneath it:

Next, you will reverse the standardization to solve for "b"

Z= (b - μ)/δ

b= (Z*δ)+μ

b= (0.674*6)+12

b= 16.044 inches

Step 3:

With the height that identifies a Koopa Troopa taller than 75% of the Goomba population determined, compute the probability of selecting that Koopa Troopa:

P(Y≤16.044)

This time, utilize the Koopa’s average height and standard deviation to find the probability:

P(Z≤(16.044-15)/3)

P(Z≤0.348)= 0.636

The likelihood of randomly selecting a Koopa Troopa that is taller than 75% of Goombas is 63.6%

I hope this information is useful!