Answer:
2.5 x 10¹⁰ ppt
5.0 x 10¹⁰ ppt
1.0 x 10¹¹ ppt
Explanation:
The term ppt denotes parts per trillion, meaning how many parts of the enzyme are present in 1 trillion parts. Percentage denotes the number of parts per 100 units. To convert the provided values from percentage to ppt:
The concentrations in ppt are:
2.5 x 10¹⁰ ppt
5.0 x 10¹⁰ ppt
1.0 x 10¹¹ ppt
Utilize the Hardy Weinburg equation pertaining to allelic frequency.
P2+2pq+q2=1
Calculating gives us 174/1378 = 0.126 = q2
Consequently, q2 equals 0.126, which means q = 0.355.
<pGiven that q = 0.355 and noting that p + q = 1, therefore
P = 1 – 0.355 = 0.645.
To determine the population of homozygous dominant (p2);
(0.645)2 x 1378 = 0.416 x 1378 = 573.
For the heterozygous population (2pq);
(2 x 0.645 x 0.355) x 1378 = 0.458 x 1378 = 631.
The number of recessive individuals (q2) equals 174.
Answer:
What impact do the genes of the parental mice have on the fur color of their offspring?
Explanation:
Review all correct components listed below that you've included in your inquiry.
format: “What impact does X have on Y?”
independent variable: genes of the parental mice
dependent variable: traits of the offspring
The antidote functioned by repairing and healing his cells. An antidote serves to cure an individual from illness or toxins.
Answer:
See the explanation below
Explanation:
Non-disjunction occurs due to the failure of homologous chromosomes to separate during meiosis.
This leads to gametes (resulting daughter cells) having either additional or fewer chromosomes compared to a standard gamete.
When a gamete with excess chromosomes unites with a normal gamete, the offspring will exhibit an extra chromosome (resulting in trisomy).
Conversely, if a gamete has one less chromosome than typical and fuses with a normal gamete, the offspring will end up with a deficit of one chromosome (monosomy).
If a chromosome with gene Aa undergoes non-disjunction during meiosis, the resulting gametes may either carry both A and a or none.
<pWhen a gamete with an
Aa gene fertilizes a standard haploid sperm (
a), the resulting zygote will possess the
genotype Aaa.If a gamete that lacks any chromosome fertilizes a normal haploid sperm, the offspring will have the genotype a.
