In the mouse, gene B can produce black pigment from a colorless precursor molecule. A mouse having at least one B allele can pro

Question

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In the mouse, gene B can produce black pigment from a colorless precursor molecule. A mouse having at least one B allele can pro

duce black pigment, whereas the homozygous recessive mouse (bb) cannot and is albino. The agouti locus (A) can convert the black pigment to brown in the presence of at least one dominant A allele, whereas the homozygous recessive (aa) cannot convert the black pigment to brown. What color fur would a mouse have with the genotype aaBB

Biology

2 answers:

lana [759] · Answer 1 · 2026-03-03T13:01:58+03:00

Answer: Black

Explanation:

Given the genotype aaBB,

aa represents a recessive allele that does not allow conversion from black to brown, thereby remaining unexpressed, while BB signifies a dominant allele responsible for black fur. Thus, the dominant BB will dictate the mouse's fur color, resulting in black fur.

11111nata11111 [592] · Answer 2 · 2026-03-03T13:00:15+03:00

Answer:

Black

Explanation:

In mice, there exists a specific colorless pigment precursor.

The presence of the B allele results in the conversion of this precursor into black pigment.
In the case of genotype bb, the mouse appears albino.

Furthermore:

If allele A is present, the black pigment transforms into brown pigment.
In genotype aa, the mouse retains its black color as the pigment does not convert to brown.

Thus, for a mouse with genotype aaBB, the colorless precursor is turned into black because of the B allele, but without an A allele, the black pigment remains unchanged, resulting in a black-furred mouse.