A classmate argues that Schwann and Schleiden are responsible for the cell theory. How do you respond? Cite facts and use logica

I'm inclined to think it is C An increase in nitrogen-fixing bacteria activity, but I’m not entirely certain

Answer:

Plant cell A has a lower water potential compared to cell B. True

Plant cell B is isotonic regarding the fluid present in the beaker. True

The water potential of plant cell B increased due to a rise in solutes inside the cell. False

Plant cell B is in equilibrium with the fluid in the beaker. True

Plant cell A possesses a higher water potential than cell B. False

Plant cell A is in equilibrium with the fluid present in the beaker. False

Explanation:

Plant cell A has a lower water potential than cell B. True

This statement holds because the water potential of A is -2 bars, while B has a water potential of zero bars.

Plant cell B is isotonic to the fluid in the beaker. = True

Isotonic solutions have equal water potential. Given that the water potential of distilled water is zero and also that of plant cell B, it confirms that plant cell B is isotonic with the beaker fluid.

An increase in solutes within plant cell B does not elevate its water potential but instead diminishes it = False.

The increase of solute inside the cell leads to the reduction of water potential.

Plant cell B being at equilibrium with the beaker’s fluid is true = True

The equilibrium occurs as plant cell B's water potential is zero, with negative solute potential balanced by the positive pressure potential.

Plant cell A's water potential being higher than that of cell B is false = False.

The water potential for plant cell A is -2 bars, while plant cell B has a higher water potential of zero.

The statement that plant cell A is at equilibrium with the beaker's fluid is false = False.

Plant cell A isn’t balanced with the beaker fluid because its negative water potential causes water to move into the cell.

c. PP

Jake exhibits a dominant trait for polydactyly, thus he must be PP or Pp. Lucy, having a normal toe count, has a recessive genotype, confirming she is pp.

If Jake were Pp, a breeding scenario of Pp X pp would result in half Pp and half pp kittens, indicating some kittens could be born with the recessive trait of 18 toes. However, none of the kittens possess 18 toes, all displaying a range of 21 to 25 toes. Therefore, Jake cannot be Pp .

Jake must be PP, as a cross of PP X pp guarantees that all kittens will have the Pp genotype, demonstrating the dominant pheno-type of polydactyly. Each kitten exhibits more than the recessive count of 18 toes, hence they are Pp. The variability in toe count arises from the trait's variable expressivity.

The reproductive isolation mechanism primarily accountable for the separation of bonobos and chimpanzees is ECOLOGICAL ISOLATION.
This type of ecological reproductive isolation is also known as TEMPORAL ISOLATION or HABITAT ISOLATION. It involves barriers that affect reproduction due to different living environments or physical separations.

Cloning may result in mutations, which is clear since creating a clone requires introducing elements into the individual to ensure authenticity.