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nydimaria
3 months ago
5

Bolts are packed into bags at a factory. Each bag should have 25 bolts in it but a bad with 22 or 28 is acceptable. Formulate an

absolute value equation that could be used to solve for the minimum and maximum number of bolts in a bag.
|x____ | = ______
x = _____(smaller number here)
x = ________(larger number here)

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Mathematics
1 answer:
zzz [12.3K]3 months ago
6 0

Answer:

The absolute value equation is |x - 25| ≤ 3.

The minimum number of bolts is 22, and the maximum is 28.

Step-by-step explanation:

We are informed that each bag should ideally contain 25 bolts, allowing for 22 or 28 as acceptable variations.

This indicates an allowable variation of ±3.

Therefore, if x represents the count of bolts in a bag, the corresponding absolute value equation is |x - 25| ≤ 3.

The minimum number of bolts is 22, while the maximum is 28.

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An electronic product contains 40 integrated circuits. The probability that any integrated circuit is defective is 0.01, and the
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Answer:

The chance that there is one or more defective integrated circuits is 33.10%.

Detailed solution:

Each integrated circuit can be either defective or not, which provides only two possible outcomes. As a result, this scenario is well-suited to be analyzed using the binomial probability distribution.

About the binomial distribution

This distribution calculates the likelihood of exactly x successes in n repeated trials where each trial has two possible results.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

Here, C_{n,x} represents the count of combinations of x items selected from n elements, described by the formula:

C_{n,x} = \frac{n!}{x!(n-x)!}

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The product contains 40 integrated circuits, so n = 40.

The probability that an individual integrated circuit is defective is 0.01, so \pi = 0.01.

Finding the probability of at least one defective circuit

There are two cases: either at least one integrated circuit is defective (probability P(X > 0)) or none are defective (probability P(X = 0)). Since probabilities sum to 1, we want to determine P(X>0).

P(X > 0) + P(X = 0) = 1

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P(X = 0) = C_{40,0}.(0.01)^{0}.(0.99)^{40} = 0.6690

P(X > 0) = 1 - P(X = 0) = 1 - 0.6690 = 0.3310

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