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Zolol
3 months ago
15

Profit:p=r-c;solve for c

Mathematics
2 answers:
zzz [12.3K]3 months ago
5 0
P=r-c
Begin by subtracting r from both sides.
p-r=-c
Now divide both sides by -1.
(p-r)/(-1)=c
This results in (-1)(p-r)=c
<span>c=-p+r
c=r-p

</span>{\boxed{\sf c=-p+r}
{\boxed{\sf c=r-p}
tester [12.3K]3 months ago
5 0
If you want to rearrange p = r - c to express c, you can follow these steps:

p = r - c         /+c
p + c = r - c + c
p + c = r       /-p
p + c - p = r - p
c = r - p

The correct form is c = r - p.
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Integrated circuits from a certain factory pass a particular quality test with probability 0.75. The outcomes of all tests are m
tester [12383]

Answer:

The anticipated number of tests required to identify 680 acceptable circuits is 907.

Step-by-step explanation:

For any circuit, there are two potential results: it either passes the test or it fails. The likelihood of passing is independent between circuits. Therefore, we apply the binomial probability distribution to address this scenario.

Binomial probability distribution

This distribution calculates the chance of obtaining exactly x successes across n trials, where x has only two possible outcomes.

To find the expected number of trials to achieve r successes with a probability p, the formula is given by:

E = \frac{r}{p}

Circuits from a specific factory pass a certain quality evaluation with a probability of 0.75.

Thus, to determine the expected number of tests needed for 680 acceptable circuits, let’s denote this as E where r = 680.p = 0.75

E = \frac{r}{p}

E = \frac{680}{0.75}

E = 907

The expected number of tests necessary to find 680 acceptable circuits is 907.

8 0
2 months ago
Which of the following represents the general term for the sequence 2, 4, 6, 8, 10, . . .?
zzz [12365]
A(n)=a(1)+(n-1)d=
a(n)=2+(n-1)2=2+2n-2=2n
7 0
3 months ago
Read 2 more answers
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