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Leno4ka
1 month ago
10

Grace claims that the interquartile range of a data set is never equal to its range. Which type of set can be used to prove or d

isprove her claim?
A. A set consisting of identical elements will prove her claim.
B. A set consisting of unequal elements will prove her claim.
C. A set consisting of identical elements will disprove her claim.
D. A set consisting of unequal elements will disprove her claim.
Mathematics
2 answers:
Svet_ta [12.7K]1 month ago
6 0

C is the right answer......................................

babunello [11.8K]1 month ago
6 0
It could be either C or D, but I think C is the correct choice.
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Noah drew a scaled copy of Polygon P and labeled it Polygon Q. If the area of Polygon P is 5 square units, what scale factor did
babunello [11817]

Answer:

The scale factor equates to 3.

Detailed explanation:

Please refer to the provided image for clarity regarding this issue.

We know that

If two shapes are similar, then the ratio of their areas corresponds to the square of the scale factor.

Let

z -----> scale factor

x -----> area of polygon Q

y ----> area of polygon P

Thus, we have

z^{2}=\frac{x}{y}

so, we proceed with

y=5\ units^2

Determining the area of polygon Q

The polygon Q can be divided into five distinct squares.

Refer to the additional figure N 2.

The area of polygon Q, which represents the total area of the five squares, is

x=5(3^2)=45\ units^2

Calculating the scale factor

z^{2}=\frac{x}{y}

Thus, we derive

x=45\ units^2

y=5\ units^2

By substituting the values, we find

z^{2}=\frac{45}{5}

z^{2}=9

Taking the square root of both sides results in

z=3

Thus,

The scale factor resolves to 3.

8 0
1 month ago
Read 2 more answers
The data set represents the number of rings each person in a room is wearing. 0, 2, 4, 0, 2, 3, 2, 8, 6 What is the interquartil
Leona [12618]
D1,..,d9 = 0,0,2,2,2,3,4,6,8 //there are 9 values, presented in ascending order
Q2 (median) = d5 = 2 //middle value
Q1 = (d2+d3) / 2 = (0+2)/2 = 1
(Q1 represents the median of d1,d2,d3,d4, but as there is no singular middle element among four, the average is computed)
Q3 = (d7+d8) / 2 = (4+6)/2 = 5
interquartile range = IQR = Q3 - Q1 = 5 -1 = 4
final answer: 4

4 0
1 month ago
Read 2 more answers
PATS, PETE AND KOFFI ANNUAL SALARIES AGGREGATE TO 200,000.00 A YEAR PETE MAKES $11000.00 MORE THAN KOFFI AND PAT MAKES $1000.00
zzz [12365]

Respuesta:

El salario mensual de Koffi: $3500 ($42000 anuales)

Salario mensual de Pete: $4416.7 ($53000 anuales)

Salario mensual de Pat: $8750 ($105000 anuales)

Explicación paso a paso:

Sea x el salario anual de Pat

Sea y el salario anual de Pete

Sea z el salario anual de Koffi

Según el enunciado, sus salarios anuales suman $200000 es decir, x + y + z= $200000

Pete gana $11000 más que Koffi anualmente, lo que significa que y = $11000 + z

Pat gana $1000 menos que el doble (×2) del salario anual de Pete, es decir, x = 2y - $1000

Así, tenemos 3 ecuaciones:

(1)..... x + y + z= $200000

(2).... y = $11000 + z

(3).... x = 2y - $1000

Primero, sustituimos y en la ecuación (3), es decir,

x = 2(11000 + z) - 1000

x = 22000 + 2z - 1000

x = 21000 + 2z............ (4)

Luego incorporamos las ecuaciones (4) y (2) en la ecuación (1) para encontrar z:

x + y + z = 200000

21000 + 2z + 11000 + z + z = 200000

4z + 32000 = 200000

4z = 200000 - 32000

4z = 168000

z = 42000

Así que z (salario anual de Koffi) es de $42000.

Para conocer y, sustituimos z en la ecuación (2).

y = 11000 + z

y = 11000 + 42000

y = 53000

Por lo tanto, y (salario anual de Pete) es de $53000

Para hallar x, sumamos $42000 y $53000, y restamos de $200000 es decir, 42000 + 53000 = 95000

200000 - 95000 = 105000

Por lo tanto, x (salario anual de Pat) es de $105000.

Para obtener el salario mensual de cada individuo, dividimos su salario anual entre 12:

Koffi (z) = 42000/12 = $3500

Pete (y) = 53000/12 = $4416.7

Pat (x) = 105000/12 = $8750

4 0
1 month ago
Which of the following graphs could be a representation of a geometric sequence? Check all that apply
PIT_PIT [12445]

Answer:

\boxed{\text{A, B, and C}}

Detailed explanation:

The formula that defines a geometric series is aₙ = a₁rⁿ⁻¹.

This parallels the exponential series y = a₀rⁿ.

A key distinction is that for geometric series, n must be a positive integer.

Consequently, the graph of a geometric series originates at some point on the y-axis and either escalates quickly or declines steadily toward the x-axis.

In Graph A, the resulting y values are 5/2⁰, 5/2¹, 5/2², and 5/2³, illustrating exponential decay.

In Graph B, the y values progress as 3¹, 3², and 3³, indicating exponential growth.

In Graph C, the y values are 2¹, 2², 2³, and 2⁴, which is also an example of exponential growth.

However, in Graph D, the y values show a steady increase of 1.5, making it an arithmetic series.

\boxed{\textbf{A, B, and C}} might represent a geometric series.

4 0
1 month ago
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The number of pages that Carolyn wrote in her journal each day from Monday to Friday is shown below: 9, 8, 12, 6, 10. What is th
Zina [12379]

Answer:

On average, she wrote 9 pages each day.

Step-by-step explanation:

The quantity of pages Carolyn penned in her journal from Monday to Friday is given as follows:

Monday = 9

Tuesday =8

Wednesday = 12

Thursday = 6

Friday = 10

Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\Mean =\frac{9+8+12+6+10}{5}

Mean=9

Thus, she wrote an average of 9 pages each day.

4 0
1 month ago
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