Explain how knowing 1 + 7 helps you find the sum of 7 + 1

We have to calculate the result of the division problem.

To determine the result, long division will be employed.

)

Initially, we quotient with x since fits into , x times.

Thus, we have:

)(x

After subtraction, we obtain:

We can see that fits into , -2 times; therefore, the next addition to the quotient will be -2. This results in a final quotient of (x-2).

Answer:

Using integer tiles, you would either add five sets of negative two tiles or take away two sets of five positive tiles. On the number line, you would jump 5 spaces to the left

Step-by-step explanation:

I hope this is helpful :)

In the absence of a specific question posed, below are the potential inquiries along with their respective answers:

P(fewer than 4 tosses)
= P(one toss) + P(two tosses) + P(three tosses)
= (3/4) + (3/4)(1/4) + (3/4)(1/4)^2
= 0.984375


Expected value
= 1 / p
= 1 / (3/4)
= 4 / 3

Variance
= (1 - p) / p^2
= (1 - (3/4)) / (3/4)^2
= (1/4) / (9/16)
= 4 / 9

Standard deviation
= sqrt(Variance)
= sqrt(4 / 9)
= 2 / 3

Assume that the number of overdue days for the library book is X, and the total fine is Y.

Liability charges a fee of $0.30 per day for lateness,

Thus, for one day late, the fee equals: 1 * $0.30

For X days late, the fee becomes: X * $0.30.

The total fee Y corresponds to being X days late, so: Y = 0.30 * X.

Next, we'll verify which possible answers satisfy the equation Y = 0.30 * X.

Options one (-3, -0.9) and two (-2.5, -0.75) are invalid since the number of late days cannot be negative, and these give negative values for X.

Option three (4.5, 1.35) is also incorrect because the library charges per whole day; 4.5 days is not an integer, so they would charge 4 or 5 days, not 4.5.

Option four (8, 2.40) matches the equation perfectly:

Y = 0.30 * X

2.40 = 0.30 * 8

2.40 = 2.40.

Therefore, the only correct answer is option four (8, 2.40).

Answer:

u(t)  = -(3 + w^2 ) cos t /(1- w^2)cos t + 7 sin t + 8 cos wt /(1- w^2)

Step-by-step explanation:

The characteristic equation is k² + 1 = 0, which leads to k² = -1, resulting in k = ±i.

The roots are k = i or -i.

The general solution takes the form  u(x)=C₁cosx+C₂sinx.

Applying the method of undetermined coefficients, we have

Uc(t) = Pcos wt  + Qsin wt

Calculating the derivatives gives us Uc’(t) = -Pwsin wt  + Qwcos wt

And differentiating again yields Uc’’(t) = -Pw^2cos wt  - Qw^2sin wt

With the equation U’’ + u = 8cos wt, we substitute:

-Pw^2cos wt  - Qw^2sin wt + Pcos wt  + Qsin wt = 8cos wt.

This simplifies to (-Pw^2 + P) cos wt   + (-Qw^2 + Q) sin wt = 8cos wt.

From -Pw^2 + P = 8, we find P= 8  /(1- w^2).

From -Qw^2 + Q = 8, we can conclude Q = 0.

Thus, Uc(t) = Pcos wt  + Qsin wt = 8 cos wt /(1- w^2).

Combining gives us U(t) = uh(t ) + Uc(t)

     = C1cos t + c2 sin t + 8 cos wt /(1- w^2).

Initial conditions yield:

U(0) = C1cos(0) + c2 sin (0) + 8 cos (0) /(1- w^2)

Which leads us to C1 + 8 /(1- w^2) = 5

So C1 = 5 - 8 /(1- w^2) = -(3 + w^2 ) /(1- w^2).

Next, taking the derivative:

U’(t) = -C1 sin t + c2 cos t - 8 w sin wt /(1- w^2).

Evaluating at t = 0 gives us:

U’(0) = -C1 sin (0) + c2 cos (0) - 8 w sin (0) /(1- w^2) = 7.

Thus, c2 = 7.

  u(t)  = -(3 + w^2 ) cos t /(1- w^2)cos t + 7 sin t + 8 cos wt /(1- w^2)