The independent variable in an experiment is the one that is deliberately modified or adjusted in order to observe its effects.
In this case, the varying amounts of caffeine administered to the dogs are the factor that changes—the control group receives no caffeine, the second group gets 10 mg of caffeine, while the third group gets 50 mg of caffeine each.
Thus, the amount of caffeine given to the dogs is the independent variable being altered.
Answer:
A) programs for water purification
If the water that is available to people is cleaner, they are more likely to use it frequently for hygiene purposes.
Mary initially saw a doctor who wasn't trained in drawing blood or taking x-rays. She subsequently visited a different place that specializes in those procedures.
<span>My suspicion is that the situation could be indicative of an asthma episode. The presence of coarse rhonchi lung sounds and the rate of breathing support this concern. It appears there is an obstruction in the airway. If it’s not asthma, then he might be choking on something.</span>
Utilize the Hardy Weinburg equation pertaining to allelic frequency.
P2+2pq+q2=1
Calculating gives us 174/1378 = 0.126 = q2
Consequently, q2 equals 0.126, which means q = 0.355.
<pGiven that q = 0.355 and noting that p + q = 1, therefore
P = 1 – 0.355 = 0.645.
To determine the population of homozygous dominant (p2);
(0.645)2 x 1378 = 0.416 x 1378 = 573.
For the heterozygous population (2pq);
(2 x 0.645 x 0.355) x 1378 = 0.458 x 1378 = 631.
The number of recessive individuals (q2) equals 174.
