If LN=54 and LM=31, find MN

To find the total amount owed, convert the sales tax of 6.25% into a decimal by turning it into 0.0625. Multiplying this by 600 gives 37.5, then adding that to 600 results in a total of.... $637.5 Yw (:

The corresponding scales are:

3 cm for 15 km translates to 1 cm for 5 km ⇒ answer A

5 mm for 2.5 km translates to 1 cm for 5 km ⇒ answer D

1 mm for 500 m translates to 1 cm for 5 km ⇒ answer E

Detailed explanation:

To engage with this problem:

1. Given that 1 cm is equivalent to 5 km, all provided answers must

 be converted to cm and km

2. Determine the matching scales against the provided scale

A.

Since 3 cm indicates 15 km

- Divide both values by 3

Thus, 1 cm indicates 5 km

3 cm for 15 km equates to 1 cm for 5 km

B.

Since 1 mm signifies 150 km

- Convert mm to cm

Since 1 cm = 10 mm

Thus, 1 mm = cm = 0.1 cm

So, 0.1 cm indicates 150 km

- Then multiply both by 10

So, 1 cm indicates 1500 km

1 mm to 150 km does not match with 1 cm to 5 km

C.

Since 5 cm signifies 1 km

- Divide both by 5

Thus, 1 cm signifies 0.2 km

5 cm to 1 km does not match with 1 cm to 5 km

D.

Since 5 mm signifies 2.5 km

- Convert mm to cmSince 1 cm = 10 mm

Thus, 5 mm = cm = 0.5 cm

Therefore, 0.5 cm indicates 2.5 km

- Divide both by 0.5

Therefore, 1 cm represents 5 km

5 mm to 2.5 km corresponds to 1 cm to 5 km

E.

Since 1 mm signifies 500 m

- Convert mm to cm

Since 1 cm = 10 mm

So, 1 mm = cm = 0.1 cm

- Convert m to km

Since 1 km = 1000 m

Thus, 1 m = = 0.001 km

Thus, 500 m = = 0.5 km

Thus, 0.1 cm indicates 0.5 km

- Multiply both by 10

Thus, 1 cm represents 5 km

1 mm to 500 m corresponds to 1 cm to 5 km

Learn more:

You can learn more about equivalent measurements in

c) Step-by-step breakdown: The collision rate is 1.2 incidents per 4 months, which can be expressed as 0.3 incidents monthly. Therefore, the Poisson distribution for the variable X representing monthly collisions is defined as P(X = x) =... for x ∈ N ∪ {0} = 0 otherwise. (1) Where X = 0 denotes no collisions during a 4-month timeframe, substituting gives P(X = 0) =... (2). For a 4-month period, P(No collision in 4 month period) =... (3). Two collisions in a 2-month span translate to 1 per month, thus P(X =1) =... (4). Over 2 months, P(2 collisions in a 2 month period) =... (5). One collision over a 6-month period equates to P(1 collision in 6 months period) =... (6). Consequently, P(1 collision in 6 month period) results in... (7). For no collisions in a 6-month period, P(No collision in 6 months period) =... (8). Finally, the probability of 1 or fewer collisions over six months is P(1 or fewer collision in 6 months period) = (8) + (7) = 0.0785 + 0.1653.

Answer:

(a) 4i iterations

(b) "i × n" iterations

Step-by-step explanation:

(a) The provided algorithm segment shows:

for i:= 1 to 4, (Outer loop)

for j:= 1 to i (Inner loop)

next j,

next i

The inner loop executes i times while the outer loop completes 4 cycles.

The inner loop’s total execution when the full algorithm runs is:

= i × 4

= 4i iterations

(b) In the given algorithm segment;

for i:= 1 to n, (Outer loop)

for j:= 1 to i (Inner loop)

next j,

next i

where n denotes a set of positive integers.

<pthe inner="" loop="" also="" runs="" for="" times="" and="" the="" outer="" times.=""><pthus the="" total="" iterations="" of="" inner="" loop="" for="" entire="" algorithm="" is:="">

= i × n

= "i × n" iterations

</pthus></pthe>

Answer:

I’d say it’s moderate in my opinion

Step-by-step explanation:

I might not be correct, so it’s best to wait for another person's input if my answer isn’t what you seek