Response:
Detailed explanation:
The length of the pool is longer than its width by 8 meters.
If we designate L as length and W as width, we can express this as:
L = 8 + W
We also know that the area amounts to 105 m squared.
Note:
Area of a Rectangle = Length x Width
Thus, 105 = (8 + W) x W
To adjust the equation, subtract 105 from both sides:
Without specific options available, I can provide guidance on where to focus your attention.
The end behavior of a function refers to how the graph behaves (upwards or downwards) as it nears positive or negative infinity within its domain. Essentially, we’re investigating the direction the graph tends towards on both sides.
In this scenario, as the value of x grows, the graph descends, while it ascends when x diminishes. Seek out a comparable occurrence.
The attached graph shows the moment when his catch surfaced at (35, 0). Given that it ascends consistently, the graph is linear. We need to establish the starting depth before he reeled it in. Using the equation d=rt, where d represents depth, r is the speed, and t is the time, we can find the distance traveled to reach the surface. Setting up the equation yields: d = 0.1(35). This indicates the catch traveled 3.5 m from a starting point of 3.5 m underwater, ascending at a rate of 0.1 m per second.
Part A
To identify the values of x that make 2x−1 positive
⇒ 2x - 1 > 0
⇒ 2x > 1
⇒ x > 
As a result, for any x greater than
, the expression 2x-1 is positive
Part B
To find values of y making 21−37 negative
⇒ 21-3y < 0
⇒ 21 < 3y
⇒ 7 < y
Thus, for all y values exceeding 7, the expression 21-3y is negative
Part C
To identify values of c that digit 5−3c greater than 80
⇒ 5-3c > 80
⇒ -3c > 75
⇒ -c > 25
⇒ c < -25
Therefore, for values of c less than -25, the expression 5-3c surpasses 80
Each LED bulb, along with installation labor, is priced at
.. $6.95 +$3 = $9.95
For 100 bulbs over a span of 10 years, that equals (100*10) = 1000 bulb·years. At $9.95 per bulb, 5 bulb·years are obtained, and thus the projected total cost for 1000 bulb·years is
.. (1000 b·y)*($9.95/(5 b·y)) = $1990
In summary, for a decade, the installation and changes of 200 bulbs in 100 lamps amount to $1990. Therefore, the yearly cost is...
.. $1990/(10 yr) = $199/yr
