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san4es73
29 days ago
14

Explain how the maps above depict the relationship between neocolonialism and human development.

Geography
2 answers:
Mkey [231]29 days ago
7 0

Answer:

The initial map displays the countries colonized in 1945. European nations seized weak and struggling countries to bolster their economies. The next map, more than half a century later, reveals that a large portion of the intermediate to less developed countries originated as colonies of currently prosperous nations. This reinforces concepts of neocolonialism, illustrating how former colonies are progressing towards industrialization and economic self-sufficiency while still facing restrictions and influence from their past colonizers.

Mkey [231]29 days ago
4 0

The first map illustrates the nations that were colonized in 1945. European countries established their dominance over economically vulnerable states to support their financial systems. In the second map, over five decades later, it can be observed that most moderately developed or underdeveloped countries were prior colonies of the currently developed nations. This outcome reinforces the notion of neocolonialism, highlighting that although former colonies are striving for industrialization and economic sovereignty, they are still influenced and hindered in part by their former colonizers.

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Which of the following accurately lists physical factors that help constitute a region?
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Answer:

Since no options were provided, I will answer generally.

Regions are defined as areas sharing common traits, thus a region in this context indicates an area characterized by physical factors.

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20 days ago
The hypotenuse of right triangle ABC, line segment AC, measures 13 cm. The length of line segment BC is 5 cm. What is the approx
expeople1 [203]

Answer:  44.8\°

Explanation:

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AC^{2}=AB^{2} + BC^{2}  (1)

AB^{2}=AC^{2} - BC^{2} (2)

AB^{2}=(13cm)^{2} - (5cm)^{2} (3)

AB=12cm (4)

Having determined the side lengths, we will now employ the sine function to find angles C and A (angle B is 90\°, noting we are discussing a right triangle):

For angle C:

sinC=\frac{Oppositeside}{Hypotenuse}

sinC=\frac{12}{13} (5)

C=sin^{-1}(\frac{12}{13}) (6)

C=67.38\° (7)

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sinA=\frac{5}{13} (8)

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A=22.62\° (10)

Calculating the angular difference:

C-A=67.38\°- 22.62\°

C-A=44.76\° \approx 44.8\°

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