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frutty
2 months ago
10

Two true-breeding stocks of pea plants are crossed. One parent has red, axial flowers, and the other has white, terminal flowers

. All F1 individuals have red, axial flowers. (Note which alleles are dominant/recessive.) The genes for flower color (red/white) and flower location (axial/terminal) assort independently. According to a traditional Mendel experiment, what is the probability of producing plants with white axial flowers in the F2 generation?

Biology
1 answer:
-BARSIC- [2.5K]2 months ago
8 0
The probability of generating plants with white axial flowers is 1/16. Based on the given illustration, all F1 offspring exhibited red axial flowers, indicating that the genes for red and axial traits are dominant over those for white and terminal traits in pea plants. Let's denote the allele for flower color as A (red) and a (white), and for flower position as B (axial) and b (terminal). The genotype of pure-breeding red axial flowers would be AABB, while pure-breeding white terminal flowers are represented as aabb. Crossing these results in F1 genotype AaBb, which shows all red axial flowers. For the F2 generation from AaBb crossed with AaBb, the progeny breakdown is: 9 A_B_ red/axial, 3 A_bb red/terminal, 3 aaB_ white/axial, and 1 aabb white/terminal. Consequently, the chance of generating plants with white axial flowers in the F2 generation is 1/16.
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