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15 days ago

The formula F=9/5(k-273.15)+32 converts a temperature from kelvin K to degrees Fahrenheit F.

Mathematics

2 answers:

Svet_ta [4.3K]15 days ago

6 0

Step One

Deduct 32 from both sides.

F - 32 = \frac{9}{5}(k - 273.15)

Step Two

Multiply each side by \frac{5}{9}.

\frac{5}{9}(F - 32) = \frac{5}{9} \times \frac{9}{5}(k - 273.15)

\frac{5}{9}(F - 32) = k - 273.15

Step Three

Add 273.15 to both sides.

\frac{5}{9}(F - 32) + 273.15 = k

Problem B

F = 180

Solve for k

k = \frac{5}{9}(F - 32) + 273.15

k = \frac{5}{9}(180 - 32) + 273.15

k = \frac{5}{9} \times 148 + 273.15

k = 82.2222 + 273.15

k = 355.3722

k = 355.4 <<< Answer

Leona [4.1K]15 days ago

4 0

Answer :

(a) $K=\frac{5}{9}\times (^oF-32)+273.15$

(b) The temperature expressed in Kelvin is 355.37 K

Detailed explanation:

To convert a temperature from Fahrenheit to Kelvin, the formula used is:

$^oF=\frac{9}{5}\times (K-273.15)+32$

Where:

$^oF$ = Fahrenheit temperature

$K$ = Kelvin temperature

(a) We can rearrange the formula to isolate Kelvin (K):

$^oF=\frac{9}{5}\times (K-273.15)+32$

$^oF-32=\frac{9}{5}\times (K-273.15)$

$\frac{5}{9}\times (^oF-32)=(K-273.15)$

Resulting in the formula:

$K=\frac{5}{9}\times (^oF-32)+273.15$

(b) Converting $180^oF$ to Kelvin (K):

$K=\frac{5}{9}\times (^oF-32)+273.15$

$K=\frac{5}{9}\times (180-32)+273.15$

$K=355.37$

Therefore, the temperature converted to Kelvin is 355.37 K

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