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Mashcka
15 days ago
8

A rectangular piece of paper has a width that is 3 inches less than its length. It is cut in half along a diagonal to create two

congruent right triangles with areas of 44 square inches. Which statements are true? Check all that apply.
Mathematics
1 answer:
babunello [3.6K]15 days ago
7 0

Answer:

A is TRUE (44 in² * 2 = 88 in²).

B is FALSE because x(x-3) = 88 for the rectangle or x(x-3)/2 = 44 for the triangle.

C is TRUE if x(x-3) = 88 leads to x² - 3x - 88 = 0.

D is TRUE:

x² - 3x - 88 = 0.

Δ = 9 + 4 * 88 = 361 = 19².

Thus, x = 11 or x = -8 (we discard negative values).

E is FALSE as 11 * 4 ≠ 88.

Step-by-step explanation:

Please correct me if I'm mistaken.

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D = 5x + 10xf solve literal equation for x
Leona [4187]

Answer:

x=\dfrac{d}{(5+10f)}

Step-by-step explanation:

The equation provided is:

d = 5x + 10xf

We need to isolate x from this equation.

Factoring out x from the right side gives us,

d=x(5+10f)

To find x, divide both sides by (5+10f),

x=\dfrac{d}{(5+10f)}

Thus, this represents the sought value for x.

4 0
7 days ago
The main span of Bridge A ​(2300 ​feet) is​ _____ percent shorter than the main span of Bridge B ​(4700 ​feet).
Svet_ta [4341]
To determine this answer, you need to calculate the percentage change.
This involves dividing the difference in lengths by the original length. We begin with the main bridge.

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11 days ago
What are three different ways to make the number 15,638 with only hundreds, tens, and ones?
zzz [4035]
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3 0
18 days ago
Read 2 more answers
Miguel spends $100 on books, five of which are hardcover and the remaining four are paperback. The prices at the bookstore are b
babunello [3666]

Answer:

$10

Step-by-step explanation:

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I hope this was helpful!!!:)

6 0
11 days ago
Kate begins solving the equation StartFraction 2 Over 3 EndFraction left-parenthesis 6 x minus 3 right-parenthesis equals StartF
Leona [4187]

Answer:

(B) There is a single solution: x = 0.

Step-by-step explanation:

The equation that Kate is attempting to solve is: \dfrac{2}{3} (6x-3)=\dfrac{1}{2}(6x-4)

\dfrac{2(6x-3)}{3}=\dfrac{(6x-4)}{2}\\\dfrac{2*3(2x-1)}{3}=\dfrac{2(3x-2)}{2}\\4x-2=3x-2\\$Adding two both sides$\\4x=3x\\4x-3x=0\\x=0

Consequently, this equation results in one solution: x = 0.

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6 days ago
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