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hram777
18 days ago
9

A basketball is rolling with a velocity of 0.5 meters/second relative to the ground and due north. A tennis ball is rolling with

a velocity of 0.25 meters/second relative to ground in the same direction of the basketball. Find the velocity of the basketball relative to tennis ball.
Mathematics
1 answer:
Inessa [9K]18 days ago
5 0
Let’s clarify this: the basketball moves faster, indicating the tennis ball won’t be able to catch up. Therefore, we utilize the formula:
Vr=Vb-Vt
<span>=0.5-0.25=0.25
</span>Thus, the relative speed is <span>0.25m/s.
I hope this is helpful.</span>
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Choose the correct item from each drop-down menu to factor the trinomial 6y2 + 19y + 15 by grouping.
AnnZ [9099]

Answer: (3y - 5) • (2y - 3)

Step-by-step explanation: 6y2 - 10y - 9y - 15

2.1 Factoring 6y2-19y+15

The leading term is 6y2, with a coefficient of 6.

The middle term is -19y, having a coefficient of -19.

The last term is the constant, which is +15.

5 0
26 days ago
In a school of 2100 students, the ratio of teachers to students is 1:14. Some teachers join the school and the ratio changes to
zzz [9080]

Answer:

50 Educators

Step-by-step explanation:

To tackle this question, the initial step is to calculate the amount of teachers prior to the addition of new staff. For this, I devised Model 1. In this model, teachers are positioned at the top of the ratio and students at the bottom. The variable X represents the number of teachers we are determining. Utilizing this model, I computed 2,100 multiplied by 1 (2,100) and then divided by 14 to conclude there were 150 teachers. Next, I formed a similar model with the updated student-teacher ratio (Model 2). This time, I multiplied 2,100 by 2 (which is 4,200) and divided by 21 to ascertain there are 200 teachers. Having established both the initial and the increased counts of educators, subtracting the original from the new gives you the tally of new teachers, which results in an increase of 50 teachers.

6 0
17 days ago
The equation of the tangent plane to the ellipsoid x2/a2 + y2/b2 + z2/c2 = 1 at the point (x0, y0, z0) can be written as xx0 a2
PIT_PIT [9117]

Answer:

The tangent plane equation for the hyperboloid

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=1.

Step-by-step explanation:

We have

The ellipsoid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}+\frac{z^2}{c^2}=1

The equation for the tangent plane at the point \left(x_0,y_0,z_0\right)

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}+\frac{zz_0}{c^2}=1  (Given)

The hyperboloid's equation is

\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}{c^2}=1

F(x,y,z)=\frac{x^2}{a^2}+\frac{y^2}{b^2}-\frac{z^2}[c^2}

F_x=\frac{2x}{a^2},F_y=\frac{2y}{b^2},F_z=-\frac{2z}{c^2}

(F_x,F_y,F_z)(x_0,y_0,z_0)=\left(\frac{2x_0}{a^2},\frac{2y_0}{b^2},-\frac{2z_0}{c^2}\right)

The tangent plane equation at point \left(x_0,y_0,z_0\right)

\frac{2x_0}{a^2}(x-x_0)+\frac{2y_0}{b^2}(y-y_0)-\farc{2z_0}{c^2}(z-z_0)=0

The tangent plane equation for the hyperboloid is

\frac{2xx_0}{a^2}+\frac{2yy_0}{b^2}-\frac{2zz_0}{c^2}-2\left(\frac{x_0^2}{a^2}+\frac{y_0^2}{b^2}-\frac{z_0^2}{c^2}\right)=0

The tangent plane equation

2\left(\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}\right)=2

Hence, the required tangent plane equation for the hyperboloid is

\frac{xx_0}{a^2}+\frac{yy_0}{b^2}-\frac{zz_0}{c^2}=0

7 0
1 month ago
The sequence 6, 18, 54, 162, … shows the number of pushups Kendall did each week, starting
Svet_ta [9500]

a) The sequence is geometric.

b) The subsequent term is 486

c) The rule is: a_n=6(3)^{n-1}

The 20th term will be: a_{20}=6973568802

Step-by-step explanation:

The series 6, 18, 54, 162, ... depicts the number of push-ups Kendall performed each week, starting from her initial week of exercise.

Part a) Is this sequence arithmetic or geometric?

An arithmetic sequence has a constant difference between consecutive terms.

In the given series 6, 18, 54, 162,

18-6 = 12

54-18= 36

The differences are not constant, thus it isn’t arithmetic.

A geometric sequence maintains a constant ratio between consecutive terms.

In this series 6, 18, 54, 162,

18/6 = 3

54/18 = 3

162/54 = 3

The ratios remain constant; therefore, the sequence is geometric.

The sequence in question is geometric.

Part b) How can you determine the next number in the series?

The next number can be calculated using the following formula:

a_n=a(r)^{n-1}

where a_n= nth term

a= first term

r= common ratio

The next number represents the 5th term of the sequence.

To find the 5th term:

a_n=a(r)^{n-1}\\a_5=6(3)^{5-1}\\a_5=6(3)^4\\a_5=6*81\\a_5=486

Thus, the next term in the sequence is 486

Part c) What is the rule for determining the 20th week? Calculate the 20th week.

The rule for determining the 20th week is:

a_n=6(3)^{n-1}

Here n=20

Calculating the 20th week

a_n=6(3)^{n-1}\\a_{20}=6(3)^{20-1}\\a_(20)=6(3)^{19}\\a_{20}=6973568802

5 0
1 month ago
A builder buys bricks at the rate of $4.50 per brick for the first 10, $3.50 per brick for the next 10, and $2.50 for any additi
babunello [8412]
Purchasing the first 10 bricks at $4.50 each totals $45. The subsequent 10 bricks at $3.50 each add $35. This uses $80, leaving $20 to buy bricks priced at $2.50 each, allowing for 8 more bricks. Altogether, $100 can buy 28 bricks.

8 0
1 month ago
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