A falling blood ph and a rising partial pressure of carbon dioxide due to pneumonia or emphysema indicates ________.

Respuesta:

A partir del peso molecular dado - 17,000, la proteína de los glóbulos rojos es Hemoglobina A (Hb A).

Explicación:

La técnica utilizada para la separación de moléculas de proteínas según su tamaño molecular en el estudio de biología molecular, junto con un marcador de proteína de referencia para identificar el tamaño exacto de proteína desconocida, se conoce como electroforesis en gel de poliacrilamida con SDS. Durante el proceso de separación de proteínas, ADN y ARN, entre otros, el dodecil sulfato de sodio se utiliza como un compuesto orgánico sintético empleado como tensioactivo en la solución de lisis.

Con base en el peso molecular dado - 17,000, la proteína en los glóbulos rojos es Hemoglobina A (Hb A). Su función consiste en transportar oxígeno desde los órganos respiratorios hacia el resto del cuerpo y tejidos. La Hb A se presenta en forma de tetámero, es decir, contiene cuatro subunidades que consisten en dos subunidades alfa y dos beta, cada una compuesta por 141 y 146 residuos de aminoácidos, respectivamente. Cada subunidad tiene un tamaño molecular de aproximadamente 16,000 daltones y son estructuralmente similares y del mismo tamaño.

Answer:

This is due to the favorable market price of silk.

Explanation:

The cultivation of silk improves the economic status of both individuals and the nation, as silk commands high prices in the marketplace driven by its widespread use across multiple industries. Products such as clothing, tires, parachutes, and surgical sutures utilize silk. When silk is sold at premium prices, it directly enhances the financial situations of those involved in its cultivation, and the country benefits through exports to others.

The arrangement of the amino acid sequence begins with the α-amino group residue and concludes with an α-carboxyl group at the end. This arrangement is referred to as the primary structure of the protein molecule.

Different allele frequencies are expected in the two groups.

North American:

72 birds altogether => 144 total alleles

From 72, 55 birds have short plumes, hence 17 are short-plumed.

q^2 = (2*17) / 114 = 0.236

Frequency(short plume allele) = q = 0.486

Frequency(long plume allele) = p = 1 - q = 0.514

Thus, from the North American group:

0.486 * 114 = 55 long plume alleles

0.514 * 114 = 59 short plume alleles

South American:

252 birds totaling => 504 alleles

Out of 252 birds, 75 have long plumage, 177 are short-plumed.

q^2 = (2*177) / 504 = 0.702

Frequency(short plume allele) = q = 0.838

Frequency(long plume allele) = p = 1 - q = 0.162

Thus, from this South American group:

0.162 * 504 = 82 long plume alleles

0.838 * 504 = 422 short plume alleles

For the combined population:

55 + 82 = 137 long plume alleles

59 + 422 = 481 short plume alleles

137 + 481 = 618 total alleles

p = 137/618 = 0.222

q = 481/618 = 0.778

The new population reflects the p and q from this blended result. It consists of 1000 individuals. The share of long plumed birds will be the sum of homozygous long plumed and heterozygous long plumed, calculated as: p^2 + 2pq, which you multiply by the population count of 1000 for the outcome.

population size * (p^2 + 2pq) = 1000 * (0.222^2 + 2*0.222*0.778) = 395 birds (final result)