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Ugo
17 days ago
7

Clara lends half her collection of formal dresses, d, to her sister, Susan. Clara then buys four more dresses. If she has 12 now

, write an equation to show how many dresses Clara had originally.
Mathematics
1 answer:
Inessa [9K]17 days ago
6 0

Answer:

16

Step-by-step explanation:

a:2+4 =12

a:2=12-4

a:2=8

a=8 ×2

a=16 dresses

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Which formula can be used to describe the sequence? -2/3,-4,-24,-144...
lawyer [9240]

The formula that describes the sequence is a_{n}=\frac{-2}{3}(6)^{n-1}

Step-by-step explanation:

The nth-term formula for a geometric sequence is a_{n}=a(r)^{n-1}, where

  • a represents the first term of the sequence
  • r signifies the common ratio between any two consecutive terms
  • r=\frac{a_{2}}{a_{1}} = \frac{a_{3}}{a_{2}}

∵ The sequence is \frac{-2}{3}, -4, -24, -144,.......

∵ The first term is \frac{-2}{3}

∵ The second term is -4

∴ \frac{-4}{\frac{-2}{3}}=6

∵ The third term is -24

∴ \frac{-24}{-4}=6

∵ The fourth term is -144

∴ \frac{-144}{-24}=6

∵  \frac{a_{2}}{a_{1}} = \frac{a_{3}}{a_{2}} =  \frac{a_{4}}{a_{3}} = 6

∴ There is a consistent ratio between two consecutive terms

∴ The sequence qualifies as a geometric sequence

∵ The formula for the nth term of the geometric sequence is a_{n}=a(r)^{n-1}

∵ a = \frac{-2}{3}

∵ r = 6

∴ The equation for the sequence is a_{n}=\frac{-2}{3}(6)^{n-1}

The formula that can be employed to outline the sequence is a_{n}=\frac{-2}{3}(6)^{n-1}

Learn more:

You can explore more about sequences in

8 0
8 days ago
A picture is photocopied by using a scale factor of 2. Each side of the photocopy of the picture is. enlarged by a factor of 2.
PIT_PIT [9121]

Answer:

Using a scale of 2" means "will take the original and enlarge it to twice its size".

Thus, the resulting photocopy will be double the dimensions of the original.

Step-by-step explanation:

5 0
1 day ago
Read 2 more answers
A city determines that a planned community must have at least 4 acres of developed and open space, and the difference
lawyer [9240]

Answer:

The attached figure illustrates the graph.

Step-by-step explanation:

Let

x represents the count of open acres

y depicts the total developed acres

It is established that

x+y \geq 4 corresponds to inequality A

x\leq 1 corresponds to inequality B

Keep in mind that

if the open acres, x, is limited to a maximum of 1, then it follows that x must adhere to ≤ 1

The system of equations can be solved by graphing

The solution is found in the shaded area (Note Negative acreage counts are not permissible)

The attached figure serves as a visual representation.

3 0
12 days ago
A major department store chain is interested in estimating the mean amount its credit card customers spent on their first visit
Inessa [9006]

Answer: D) \$50\pm\$11.08

Step-by-step explanation:

Based on the provided information, we have

Sample size: n= 15

sample mean: \overline{x}=\$50.50

Sample standard deviation: s= $20

Since the population standard deviation is not known, we utilize a t-test.

For a significance level of 95% confidence: \alpha=1-0.95=0.05

Critical t-value : t_{n-1, \alpha/2}=t_{014,0.025}=2.145  [Using the Student's t-value table]

The required 95% confidence interval yields:-

\overline{x}\pm t_{n-1, \alpha/2}\dfrac{s}{\sqrt{n}}\\\\ =\$50.50\pm(2.145)\dfrac{\$20}{\sqrt{15}}\\\\\approx \$50\pm\$11.08

Thus, the sought-after 95% confidence interval for the mean amount spent by credit card customers during their initial visit to the new store in the mall, assuming normal distribution of the spending amounts, is:

\$50\pm\$11.08

5 0
3 days ago
Which expressions are equivalent to RootIndex 3 StartRoot 128 EndRoot Superscript x? Select three correct answers.
AnnZ [9104]

Answer:

- 128 Superscript StartFraction 3 Over x EndFraction

- (4RootIndex 3 StartRoot 2 EndRoot)x

- (4 (2 Superscript one-third Baseline) ) Superscript x

Step-by-step explanation:

Considerando la ecuación dada (\sqrt[3]{128} )^{x}\\

De acuerdo con una de las leyes de índices,

(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}

Aplicando esta ley a la pregunta;

(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )

<pLos siguientes son ciertos de acuerdo con el cálculo presentado

128 Superscript StartFraction 3 Over x EndFraction

(4RootIndex 3 StartRoot 2 EndRoot)x

(4 (2 Superscript one-third Baseline) ) Superscript x

5 0
1 month ago
Read 2 more answers
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