Question #5 How does the computer decide which path to follow in a selection control structure?

According to the rule of 72, dividing 72 by the interest rate gives the time needed to double your investment. With an interest rate of 5.6%, we calculate 72/5.6 = 12.86 years. Thus, to increase the amount from $1850 to $3700, it would take approximately 12.86 years, suggesting that by late 1992 the balance would reach $3700.

The answer is back up

Answer:

input price

set change to one hundred minus price

set quarter to change divided by 25

set change to change mod 25

set dime to change divided by 10

set change to change mod 10

set nickel to change divided by 5

set change to change mod 5

set penny to change

print "You acquired an item for price cents and paid me a dollar. Your change is: "

if quarter is equal to 1

print quarter

else if quarter is greater than 1

print quarter with "quarters"

if dime is equal to 1

print dime

else if dime is greater than 1

print dime with "dimes"

if nickel is equal to 1

print nickel

else if nickel is greater than 1

print nickel with "nickels"

if penny is equal to 1

print penny

else if penny is greater than 1

print penny with "pennies"

Explanation:

A clearer way to express the pseudocode above could involve using alternative names for change as:

input price

set change to one hundred minus price

set quarter to change divided by 25

set quarter_remainder to change mod 25

set dime to quarter_remainder divided by 10

set dimes_remainder to quarter_remainder mod 10

set nickel to dimes_remainder divided by 5

set nickel_remainder to dimes_remainder mod 5

set penny to nickel_remainder

print "You purchased an item for" price"cents and provided a dollar. Your change is: "

if quarter is equal to 1

print quarter "quarter"

else if quarter is greater than 1

print quarter "quarters"

if dime is equal to 1

print dime "dime"

else if dime is greater than 1

print dime "dimes"

if nickel is equal to 1

print nickel "nickel"

else if nickel is greater than 1

print nickel "nickels"

if penny is equal to 1

print penny "penny"

else if penny is greater than 1

print penny "pennies"

Next, I will illustrate the pseudocode through an example:

Let's assume price = 75

Thus, change = 100 - price = 100 - 75 = 25

change = 25

quarter = change/25 = 25/25 = 1

quarter = 1

quarter_remainder = change % 25 = 25%25 = 0

dime = 0/10 = 0

At this point, all additional values are 0.

The following message will be displayed on the screen:

You acquired an item for 75 cents and paid me a dollar. Your change is:

Now the program proceeds to the conditional statement

if quarter == 1

This condition holds true because the value of quarter is 1

print quarter "quarter"

Subsequently, this line will appear on the screen:

1 quarter

Thus, the full output of the pseudocode is:

You acquired an item for 75 cents and paid me a dollar. Your change is:

1 quarter

Answer:

Below is the Python code with suitable comments.

Explanation:

#Input file name acquisition

filename=input('Enter the input file name: ')

#Opening the input file

inputFile = open(filename,"r+")

#Dictionary definition.

list={}

#Read and split file content using a loop

for word in inputFile.read().split():

#Check if the word exists in the file.

if word not in list:

list[word] = 1

#Increment count by 1

else:

list[word] += 1

#Closing the file.

inputFile.close();

#Output a blank line

print();

#Sorting words according to their ASCII values.

for i in sorted(list):

#Display unique words along with their

#frequencies in alphabetical order.

print("{0} {1} ".format(i, list[i]));

Ensure the cables are operational and correctly connected. Given that everything functioned well prior to the relocation, but post-move some workstations are unable to receive a valid IP, the first action should be to confirm that the cables are securely connected. If they are, also test the cables for functionality. If issues persist after this, then additional troubleshooting would be necessary.