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SpyIntel
2 months ago
8

A survey asked students whether they have any siblings and pets. the survey data are shown in the relative frequency table.

Mathematics
1 answer:
PIT_PIT [12.4K]2 months ago
5 0

Response:

The probability that a student has a pet, given they do not have any siblings is:

Option: D ( 60%)

Step-by-step breakdown:

Let A represent the situation where a student lacks a sibling.

Let B signify the occurrence that a student has a pet.

Consequently, A∩B refers to the event in which a student is without siblings but possesses a pet.

Let P denote the chance of an event happening.

We need to determine:

P(B|A)

From our knowledge:

P(B|A)=\dfrac{P(A\bigcap B)}{P(A)}

From the data provided:

P(A)=0.25

and P(A∩B)=0.15

Thus,

P(B|A)=\dfrac{0.15}{0.25}\\\\P(B|A)=\dfrac{3}{5}\\\\P(B|A)=0.6

which expressed as a percentage is:

0.6\times 100=60\%

Therefore, the probability is:

60%

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If you ask three strangers about their birthdays, what is the probability:
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1 month ago
A grocery store receives deliveries of corn from two farms, one in Iowa and the other in Ohio. Both farms produce ears of corn w
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Answer:

The number of standard deviations above the mean is z_o   = 1.4607

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The question indicates that:

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     \sigma_2= 0.01 + \sigma_1

     

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In general, the standardized score of corn weight from Iowa can be mathematically defined as:

        z  =  \frac{ 1.39 -  1.26 }{\sigma_1 }

=>     1.645 =  \frac{ 1.39 -  1.26 }{\sigma_1 }  

=>      \sigma_1 =  \frac{ 1.39 -  1.26 }{ 1.64 5}  

=>      \sigma_1  =   0.0790  

Conversely, the standardized score of corn weight from Ohio is expressed as:

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=>     z_o=  \frac{ 1.39 -  1.26 }{0.01 + \sigma_1 }  

=>      z_o =  \frac{ 1.39 -  1.26 }{  0.089}  

=>      z_o   = 1.4607

A positive value indicates this quantity represents the number of standard deviations above the mean.

4 0
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Zina [12379]

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Step-by-step explanation:

The equation 5y = 2 represents a horizontal line at y = 2/5.

This means that the y-coordinate holds the value of 2/5 = 0.4 for any x-coordinate.

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