There were 340,000 cattle placed on feed. Write an equivalent ratio that could be used to find how many of these cattle were bet

The formula , where r! is defined as 1*2*3*...r

provides the total number of combinations for forming groups of r items from a collection of n items.

For instance, with 10 items, there are C(10,6) possible ways to create groups of 6 from these 10 objects.

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Choosing 4 individuals from a total of 12 can be accomplished in:

many different ways.

All unique groupings of 4 individuals, including the husband and wife pair, can be computed as C(10, 2) ways, since we only consider the potential selections of 2 from 10 individuals to form a group of 4.

Consequently, the probability that both the husband and wife are selected is 45/495=0.09


Part 2)

The chance that one gets selected while the other does not =

P(husband selected, wife not selected) + P(wife selected, husband not selected)

These two scenarios are precisely equal, so it suffices to compute one.


Let's analyze the scenario: husband chosen, wife not selected.

Assuming the husband is selected, we need to determine the possible formations of 3 from the 11 total excluding the wife=10 individuals.

This results in:

Hence,

P(husband selected, wife not selected)=120/495=0.24

Thus, the overall probability that one is picked while the other is not =

P(husband selected, wife not selected) + P(wife selected, husband not selected) =

0.24+0.24=0.48

Result:

A) 0.09

B) 0.48

<span><span>Example<span>Simplify 3 + 5 </span>•<span> 2.</span>  </span><span> <span>3 + <span>5 </span></span>•<span> 2</span>  <span>According to order of operations, multiplication should occur before addition.</span> </span><span> 3 + 10 Next, perform the addition.</span><span>Result     </span><span>3 + 5 </span>•<span> 2 = 13</span></span>

 

 

 

<span>Example<span>ProblemSimplify 20 – 16 ÷ 4.  </span><span> <span>20 – 16 ÷ 4  </span><span>Order of operations indicates division should be completed prior to subtraction.</span> </span><span> <span>20 – 416</span>Then execute the subtraction.</span><span>Final result     </span>20 – 16 ÷ 4 =<span> 16</span></span>

Answer:

Step-by-step explanation:

First, we need to calculate how many potential credit card numbers can be created using the digits 0 through 9.

We aim to create a number that consists of 16 digits from a total of 10 digits, therefore:

The total count of possible numbers formed is . However, only 100 million of these are valid (). Let n represent the valid number of combinations.

This leads us to the probability of selecting a valid number:

P(valid) = n / N

Answer:

E(t) = [ 4cos(t), 2 sin(t) ]

Step-by-step explanation:

The equation for the ellipse can be represented as:

 (x² ÷ a² ) + (y² ÷ b² ) = 1    Here, a and b symbolize the semi-major and semi-minor axes.

In this specific instance, we have    x²/16 + y²/ 4 = 1

This expression indicates that it follows the form of (x/a)² + (y/b)² =1

Specifically in our case,    x²/16  + y²/4 = 1, which resembles                 sin²α + cos²α = 1.

By setting x = 4 cos(t), we can proceed to calculate y.

Utilizing the equation x²/16  + y²/4 = 1, we find that:

x²/16  + y²/4 = 1   ⇒    (x²  +  4y²) ÷ 16  = 1

Solving for y yields: (x²  +  4y²)  = 16    ⇒  y²  = ( 16 - x²) ÷4

Substituting x = 4 cos(t) gives us y²  =  (16 - 16cos²(t)) ÷ 4, leading to y = √4 (1 - cos²(t)).

Consequently, we have y = 2 sin(t).

Thus, the vector parameterization of the ellipse can be stated as:

E(t) = [ 4cos(t), 2 sin(t) ]

The aggregate expense for the markers is 12.