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GrogVix
13 days ago
11

Leon bought trail mix that cost $0.78 per pound. He paid $6.24 for the trail mix. How many pounds of trail mix did he buy?

Mathematics
2 answers:
zzz [9K]13 days ago
6 0
The definitive answer is 8 pounds. I hope this helps!!!!
Zina [9.1K]13 days ago
3 0
If Leon purchased trail mix costing $6.24 and he paid $0.78 per pound,

6.24/0.78 = 8 lbs.
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Gabe charges $30 to mow a lawn. Nate
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Gabe mowed 5 lawns and made $150.
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10 days ago
Why might the triangulation method not always produce an exact point (other than any measurement errors)
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Answer:

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It employs a variety of data sources, different researchers, and multiple theories or viewpoints.

Step-by-step explanation:

Research triangulation integrates various methods, data sources, diverse investigators, and assorted theories to develop a deeper insight into the situations being studied. This process fortifies qualitative research by incorporating data from multiple sources, perspectives, and methodologies.

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17 days ago
XY= 2x +1, YZ= 6x, and XZ=81
tester [8808]
 x = 27 + 3 √ 129/ 4, 27 − 3 √ 129/ 4

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 x approximates to 15.26836251, − 1.76836251

That concludes my response. I hope this is helpful. You will still need to work on finding y and z, which can be quite challenging:)
8 0
20 days ago
An angle bisector always creates two acute angles. find a counterexample to show that the conjecture is false.
Inessa [8989]
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5 0
17 days ago
Let c1(t) = eti + (sin(t))j + t3k and c2(t) = e−ti + (cos(t))j − 6t3k. Find the stated derivatives in two different ways to veri
Zina [9157]

Answer:

i ( e^{t} - e^{-t})+ j (cost-sin t)+ k (-15t^{2})

\frac{d}{dx}(e^x) = e^x

Step-by-step explanation:

Step 1:-

We have c1(t) = e^ t i + (sin(t))j + t³k

and c2(t) = e^−t i + (cos(t))j − 6t³k.

By adding c1(t) and c2(t):

c1(t)+c2(t) = e^ t i + (sin(t))j + t³k + e^−t i + (cos(t))j − 6t³k

Now, employing the derivative formula:

\frac{d}{dx}(e^x) = e^x

\frac{d}{dx}(sinx) = cosx\\\frac{d}{dx}(cosx) = -sinx

Next, differentiate with respect to 't'

\frac{d}{dt}c_{1}+ c_{2} } = e^ t i +cost j +3t^2 k - e^-t i - sintj -18t^2 k

By factoring out i, j, and k terms, we arrive at:

\frac{d}{dt}(C_{1} +C_{2} ) = i ( e^{t} - e^{-t})+ j (cost-sin t)+ k (-15t^{2})

7 0
23 days ago
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