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shusha
2 months ago
7

Round 5370288 to the nearest 100,000

Mathematics
2 answers:
Svet_ta [12.7K]2 months ago
7 0
Greetings!

To round 5,370,288 to the closest 100,000

, you should determine if the digit following the hundred thousands digit is above or below 5. If it's above 5, you increase the hundred thousands digit by 1. Conversely, if it falls below 5, you round down by filling in zeros.

When 5,370,288 is rounded to the nearest hundred thousands, it results in 5,400,000.

I hope this was helpful!:D
Leona [12.6K]2 months ago
7 0
5400000, since the 7 rounds the 8 up to 4.
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(78,104) represents the point closest to the interior.

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The equation defining the circle,

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Since the point lies on the circle, its coordinates must be,

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The distance "d" from the point to (30,40) can be calculated as,

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Next, we need to determine the value of x for which d is minimized. The minimum distance occurs when 9400-60x-80\sqrt{16900-x^2} is at its lowest value.

Let’s set up the equation,

\Rightarrow f(x)=9400-60x-80\sqrt{16900-x^2}

\Rightarrow f'(x)=-60+80\dfrac{x}{\sqrt{16900-x^2}}

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We find the critical points,

\Rightarrow f'(x)=0

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\Rightarrow 80\dfrac{x}{\sqrt{16900-x^2}}=60

\Rightarrow 80x=60\sqrt{16900-x^2}

\Rightarrow 80^2x^2=60^2(16900-x^2)

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\Rightarrow \dfrac{16}{9}x^2=16900-x^2

\Rightarrow \dfrac{25}{9}x^2=16900

\Rightarrow x=\sqrt{\dfrac{16900\times 9}{25}}=78

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Then,

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Since f''(x) is positive, the function f(x) achieves its minimum at x=78

When x is set to 78, the corresponding y value will be

\Rightarrow y = \sqrt{16900-x^2}=\sqrt{16900-78^2}=104

This leads us to conclude that the closest point is (78,104)

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