Answer:
The total probability exceeds 100%, indicating a problem with the findings; moreover, the distribution shows excessive uniformity which disqualifies it as a normal distribution.
Detailed explanation:
The sum of probabilities should be exactly 100%. When you add the probabilities of this distribution:
22+24+21+26+28 = 46+21+26+28 = 67+26+28 = 93+28 = 121
This exceeds 100%, highlighting a significant error in the results.
A typical normal distribution possesses a bell curve. If we plot the probabilities for this distribution, we'd see bars at 22, 24, 21, 26, and 28.
The bars would fail to form a bell-shaped curve, confirming that this is not a normal distribution.
7 hours 12 minutes
6 hours 46 minutes
6 hours 53 minutes
--------------------------sum
Total: 19 hours 111 minutes, which converts to (19 × 60) + 111 = 1140 + 111 = 1251 minutes
Calculate average time by dividing by 3: 1251 / 3 = 417 minutes, equivalent to 6 hours 57 minutes, which is the average delivery duration.
We consider all workers as either full-time or part-time.
36 = 24 + 12
If there are 24 or fewer full-time workers, there must be at least 12 part-time workers. (This conclusion is based on the understanding of sums.)
You can formulate the inequality in two steps. First, present and resolve an equation for full-time workers in relation to part-time workers. Then, apply the specified limit on full-time workers. This results in an inequality that can be solved for part-time workers.
Let f and p represent full-time and part-time positions, respectively.
f + p = 36... given
f = 36 - p... subtract p to express f in terms of p.
f ≤ 24......... given
(36 - p) ≤ 24.... substitute for f. This gives your inequality in terms of p.
36 - 24 ≤ p.... rearranging gives p ≥ 12........ this is the solution to the inequality
