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saul85
12 days ago
11

Calculate solute of a 0.1M NaCl solution at 25 degrees Celsius. If the concentration of NaCl inside the plant cell is 0.15M, whi

ch way will the water diffuse if the cell is placed into the 0.1M NaCl solution?
Biology
2 answers:
s2008m [1.6K]12 days ago
7 0
 The solute potential is indicated by the formula P = -iCRT, with i representing the ionization constant, C being the molar concentration, R as the pressure constant (R = 0.0831 liter * bars/mole * K), and T signifying the temperature in Kelvin (273 + °C). A 0.15 M NaCl solution at standard atmospheric pressure and 25°C has an osmotic potential of -7.4 bars, with Na+ and Cl- yielding 2 ions (in contrast to sucrose, which counts as one). Therefore, i = 2, and osmosis will drive water from the 0.1 to the 0.15 concentration.
s2008m [1.6K]12 days ago
5 0
The appropriate answer yields -7.429 bars. The solute potential within the cell is determined through the equation = -iCRT, where i denotes the number of ions, C is the solute concentration, R represents the gas constant, and T is the temperature in Kelvin. The NaCl concentration inside the plant cell stands at 0.15 M, where i = 2, R = 0.0831, and T = 298 K, equivalent to 25 degrees Celsius. Consequently, solute potential calculates to - (2 * 0.15 * 0.0831 * 298) = -7.429 bar.
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