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ohaa
11 days ago
15

Frank has X stamps and Chris has 8 more than 7 times the number of stamps Frank has. How many stamps do Frank and Chris have in

total?
A=8x
B=7x+8
C=8x+7
D=8x+8
E=56x+7
Mathematics
1 answer:
zzz [9K]11 days ago
5 0
I think the right answer is D. 8x+8;
This is because Frank possesses X stamps while Chris has 8 plus 7 times the number of stamps Frank holds, making the total 8 + 7x (which is 7 times Frank's amount), so when you add Frank's stamps (x) to 8 + 7x, it results in 8 + 8x.

I hope this was helpful!
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The graphs below have the same shape. What is the equation of the blue graph?
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Answer: OPTION B

Step-by-step explanation:

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As a consequence, considering this, the transformation takes the following structure:

g(x)=(x-h)^2+k

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Which of the following is most likely the next step in the series?
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Answer:

B. The triangle.

Step-by-step explanation:

The number of sides decreases by one as you progress down the list.

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18 days ago
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Let c1(t) = eti + (sin(t))j + t3k and c2(t) = e−ti + (cos(t))j − 6t3k. Find the stated derivatives in two different ways to veri
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Answer:

i ( e^{t} - e^{-t})+ j (cost-sin t)+ k (-15t^{2})

\frac{d}{dx}(e^x) = e^x

Step-by-step explanation:

Step 1:-

We have c1(t) = e^ t i + (sin(t))j + t³k

and c2(t) = e^−t i + (cos(t))j − 6t³k.

By adding c1(t) and c2(t):

c1(t)+c2(t) = e^ t i + (sin(t))j + t³k + e^−t i + (cos(t))j − 6t³k

Now, employing the derivative formula:

\frac{d}{dx}(e^x) = e^x

\frac{d}{dx}(sinx) = cosx\\\frac{d}{dx}(cosx) = -sinx

Next, differentiate with respect to 't'

\frac{d}{dt}c_{1}+ c_{2} } = e^ t i +cost j +3t^2 k - e^-t i - sintj -18t^2 k

By factoring out i, j, and k terms, we arrive at:

\frac{d}{dt}(C_{1} +C_{2} ) = i ( e^{t} - e^{-t})+ j (cost-sin t)+ k (-15t^{2})

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23 days ago
To better understand how husbands and wives feel about their finances, Money Magazine conducted a national poll of 1010 married
Svet_ta [9500]

Answer:

  • a. Refer to the table below
  • b. Refer to the table below
  • c. 0.548
  • d. 0.576
  • e. 0.534
  • f) i) 0.201, ii) 0.208

Explanation:

To begin with, organize the data provided:

Table: "Who excels at obtaining deals?"

                       Who Excels?

Respondent      I Am        My Spouse     We are Equal

Husband           278             127                 102

Wife                   290            111                   102

a. Create a joint probability table and utilize it to respond to the ensuing inquiries.

The joint probability table presents identical details expressed as proportions. The values from the table need to be divided by the total number of responses involved.

1. Total responses: 278 + 127 + 102 + 290 + 111 + 102 = 1,010.

2. Determine each proportion:

  • 278/1,010 = 0.275
  • 127/1,010 = 0.126
  • 102/1,010 = 0.101
  • 290/1,010 = 0.287
  • 111/1,010 = 0.110
  • 102/1,010 = 0.101

3. Construct the table containing these values:

Joint probability table:

Respondent      I Am        My Spouse     We Are Equal

Husband           0.275           0.126                 0.101

Wife                   0.287           0.110                  0.101

This table illustrates that the joint probability of identifying as a husband while choosing 'I am' equals 0.275. Each cell conveys the joint probability associated with each gender's response.

Consequently, this delineates the purpose of a joint probability table.

b. Generate marginal probabilities for Who Excels (I Am, My Spouse, We Are Equal). Provide commentary.

Marginal probabilities are computed for each row and column of the table, indicated in the margins, which is their namesake.

For the column titled "I am," it amounts to: 0.275 + 0.287 = 0.562

Similarly, perform calculations for the other two columns.

For the row designated 'Husband,' it would thus be 0.275 + 0.126 + 0.101 = 0.502. Apply the same for the row labeled 'Wife.'

Table Marginal probabilities:

Respondent      I Am        My Spouse     We Are Equal     Total

Husband           0.275           0.126                 0.101             0.502

Wife                   0.287           0.110              0.101             0.498

Total                 0.562           0.236            0.202             1.000

Notably, when summing the marginal probabilities for both rows and columns, the results will always equate to 1. This is a consistent truth for marginal probabilities.

c. Given the respondent is a husband, what is the likelihood that he believes he is better at securing deals than his wife?

This requires the utilization of conditional probability.

The goal here is to ascertain the probability of the response being "I am" when the respondent identifies as a "Husband."

Using conditional probability:

  • P ( "I am" / "Husband") = P ("I am" ∩ "Husband) / P("Husband")

  • P ("I am" ∩ "Husband) = 0.275 (obtained from the intersection of columns "I am" and rows "Husband")

  • P("Husband") = 0.502 (derived from total of row "Husband")

  • P ("I am" ∩ "Husband) / P("Husband") = 0.275 / 0.502 = 0.548

d. In the instance that the respondent is a wife, what probability exists that she believes she is superior to her husband in acquiring deals?

We seek to identify the probability wherein the response claims "I am" while the respondent is labeled a "Wife," applying the conditional probability formula again:

  • P ("I am" / "Wife") = P ("I am" ∩ "Wife") / P ("Wife")

  • P ("I am" / "Wife") = 0.287 / 0.498

  • P ("I am" / "Wife") = 0.576

e. When responding that "My spouse" is better at scoring deals, what is the likelihood that the claim originated from a husband?

We aim to compute: P ("Husband" / "My spouse")

Applying the conditional probability formula:

  • P("Husband" / "My spouse") = P("Husband" ∩ "My spouse")/P("My spouse")

  • P("Husband" / "My spouse") = 0.126/0.236

  • P("Husband" / "My spouse") = 0.534

f. When the response indicates "We are equal," what likelihood exists that this response is from a husband? What is the chance that it hails from a wife?

What is the likelihood that this response came from a husband?

  • P("Husband" / "We are equal") = P("Husband" ∩ "We are equal") / P ("We are equal")

  • P("Husband" / "We are equal") = 0.101 / 0.502 = 0.201

What is the chance the response originated from a wife:

  • P("Wife") / "We are equal") = P("Wife" ∩ "We are equal") / P("We are equal")

  • P("Wife") / "We are equal") = 0.101 / 0.498 = 0.208
6 0
1 month ago
The equation x2 – 1x – 90 = 0 has solutions {a, b}. What is a + b
PIT_PIT [9117]
X^2 - x - 90 =0
This quadratic equation is in the standard format ax^2+ bx + c
The total of the solutions can be found using -b/a (where a and b are the coefficients from the original equation, not the solutions)
The resulting answer is 1/1 = 1
8 0
1 day ago
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