Draw a model to represent the problem 6/12 divided by 1/4

Explain why the following expression is false. |x| < -4

Zina [12379]

Step-by-step explanation:

When a negative number is placed within a modulus function, the result will be positive. For instance, |-3| equals 3, |-6| equals 6, and |5| equals 5, etc.

A modulus function, expressed as |x|, is always positive unless x is zero, in which case it equals zero.

Consequently, |x| cannot be less than -4 because |x| is always non-negative. Thus, the statement is inaccurate.

8 0

2 months ago

Which is the solution of the quadratic equation (4y-3)^2=72 ?

babunello [11817]

Greetings:
<span>(4y-3)²=72
4y-3 = </span>±√72
thus, y= (3+√72) /4 or y= (3 - √72) /4

7 0

2 months ago

A customer/member owes $10.51 and pays $50.00 in cash. The change due is $39.49. Provide the amount owed using the smallest numb

Leona [12618]

The total number of bills and coins is 14.

Step-by-step explanation:

To minimize the count of bills and coins, start with the largest denominations that fit within the amount.

The change due is $39.49.

Start with:

-$20 bill (largest under $39.49)

Remaining: $19.49

-$10 bill (largest under $19.49)

Remaining: $9.49

-$5 bill (largest under $9.49)

Remaining: $4.49

Then:

4 × $1 bills (to cover $4.49)

Remaining: $0.49

-$0.25 coin (quarter)

Remaining: $0.24

2 × $0.10 coins (dimes)

Remaining: $0.04

4 × $0.01 coins (pennies)

The final composition includes:

1 twenty-dollar bill

1 ten-dollar bill

1 five-dollar bill

4 one-dollar bills

1 quarter

2 dimes

4 pennies

Totaling 14 pieces.

5 0

3 months ago

Question 1 Show all your work. Indicate clearly the methods you use, because you will be scored on the correctness of your metho

babunello [11817]

Answer:

(a) The 95% confidence interval representing the percentage of the entire U.S. population that would select American football as their preferred television sport is (0.34, 0.40).

(b) Not reasonable.

Step-by-step explanation:

Given:

n = 1000

$\hat p$ = 0.37

(a)

The confidence interval (1 - α)% for proportion p is:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

Where:

$\hat p$ = the sample proportion

n = sample size

$z_{\alpha/2}$ = critical z value.

Calculate the critical value of z for a 95% confidence level as shown:

$z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96$

*Refer to a z-table for the necessary value.

Compute the 95% confidence interval for proportion p as follows:

$CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

$=0.37\pm 1.96\times\sqrt{\frac{0.37(1-0.37)}{1000}}$

$=0.37\pm 0.03\\=(0.34, 0.40)$

Thus, the 95% confidence interval indicating the proportion of individuals in the U.S. who might say their preferred sport on TV is American football is (0.34, 0.40).

(b)

Next, we must assess if it's rational to consider that the actual percent of people in the United States who favor American football on television is 33%.

The hypothesis is defined as:

H₀: The portion of the U.S. population claiming American football as their favorite sport on television is 33%, meaning p = 0.33.

Hₐ: The proportion of people in the U.S. whose favorite sport to watch on television is not 33%, or p ≠ 0.33

This hypothesis can be verified using a confidence interval.

The decision rule:

If the (1 - α)% confidence interval contains the null value of the hypothesis, then the null hypothesis is not rejected. If, however, the (1 - α)% confidence interval excludes the null value of the hypothesis, then the null hypothesis is rejected.

The confidence interval does encompass the null value of p, which is 0.33.

<pthus the="" null="" hypothesis="" will="" be="" rejected.=""><pin conclusion="" it="" is="">not reasonable to accept that 33% represents the actual percentage of those in the U.S. whose favorite televised sport is American football.

</pin></pthus></pthe>

6 0

3 months ago