The solution to the query
The solution is found in the image attached below.
I appreciate you sharing your question. A potential solution to the problem is that 10 ones can be converted into 1 ten, resulting in the total of the ungrouped values of 4,000 + 900 + 10, which sums up to 5,000. I trust my explanation will be beneficial.
Answer:
- 128 Superscript StartFraction 3 Over x EndFraction
- (4RootIndex 3 StartRoot 2 EndRoot)x
- (4 (2 Superscript one-third Baseline) ) Superscript x
Step-by-step explanation:
Considerando la ecuación dada ![(\sqrt[3]{128} )^{x}\\](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B128%7D%20%29%5E%7Bx%7D%5C%5C)
De acuerdo con una de las leyes de índices,
![(\sqrt[a]{m} )^{b}\\= (\sqrt{m})^\frac{b}{a}](https://tex.z-dn.net/?f=%28%5Csqrt%5Ba%5D%7Bm%7D%20%29%5E%7Bb%7D%5C%5C%3D%20%28%5Csqrt%7Bm%7D%29%5E%5Cfrac%7Bb%7D%7Ba%7D)
Aplicando esta ley a la pregunta;
![(\sqrt[3]{128} )^{x}\\ = {128} ^\frac{x}{3}\\ \\= (\sqrt[3]{64*2})^{x} \\ = (4\sqrt[3]{2})^{x} \\= (4(2^{1/3} )^{x} )](https://tex.z-dn.net/?f=%28%5Csqrt%5B3%5D%7B128%7D%20%29%5E%7Bx%7D%5C%5C%20%3D%20%7B128%7D%20%5E%5Cfrac%7Bx%7D%7B3%7D%5C%5C%20%5C%5C%3D%20%28%5Csqrt%5B3%5D%7B64%2A2%7D%29%5E%7Bx%7D%20%5C%5C%20%3D%20%284%5Csqrt%5B3%5D%7B2%7D%29%5E%7Bx%7D%20%5C%5C%3D%20%284%282%5E%7B1%2F3%7D%20%29%5E%7Bx%7D%20%29)
<pLos siguientes son ciertos de acuerdo con el cálculo presentado
128 Superscript StartFraction 3 Over x EndFraction
(4RootIndex 3 StartRoot 2 EndRoot)x
(4 (2 Superscript one-third Baseline) ) Superscript x
Response:
100 percent increase
Detailed explanation:
1st garden
Length = 6 ft
Width = 4 ft
Perimeter = 2 (l+w)
= 2 (6+4) = 2(10) = 20
2nd garden
The length and width of this garden are double those of the first
Length = 2 *6 = 12
Width = 2 *4 = 8
Perimeter = 2 (l+w)
= 2 (12+8) = 2(20) = 40
Percent change = (new - old )/old * 100 percent
The first garden represents the old garden = 20 and the second refers to the new garden = 40
Substituting values in
Percent change = (40-20)/20 = 20/20 =100 *100 percent
= 100 percent increase