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Ratling
2 months ago
6

An investment fund starts at $0 and grows at a rate of $100 per month. Another fund starts at $4000 and reduces by $720 per year

. After how long will the funds have the same amount of money?
Mathematics
1 answer:
Zina [12.3K]2 months ago
6 0
The answer is: 2 years and 1 month. This duration at $100 per month totals to $2,500. The calculation is $720 per year over 2 years results in $1,440. Monthly, this amounts to $60, making the total $1,500 after adding the two figures. Therefore, $4,000 - $1,500 leaves us with $2,500.
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The scatterplot represents the total fee for hours renting a bike. The line of best fit for the data is y = 6.855x + 10.215. Whi
Inessa [12570]

Solution: A- represents the first chart


5 0
2 months ago
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Triangle KLM was dilated according to the rule DO,0.75 (x,y). What is true about the image △K'L'M'? Check all that apply. DO, 0.
Zina [12379]

The accurate statements are 0.75 (x,y) = (0.75x, 0.75y), LM is parallel to L'M', and "the vertices of the image are nearer to the origin relative to the pre-image".

Explanation:

It is stated that the triangle ABC underwent dilation as per the rule DO,0.75 (x,y)

DO, 0.75(x,y) signifies the dilation rule, where both x and y values are scaled by 0.75, indicating that the dilation, centered around the origin, has a scale factor of 0.75. The representation for this dilation would be,

(x,y)\rightarrow (0.75x,0.75y)

Consequently, the first statement holds true.

Since both x and y coordinates are scaled down by 0.75, the sides of the image are parallel, but shorter, with a scale of 0.75 compared to the pre-image’s sides.

Thus, the second statement "LM is parallel to L'M'" is also accurate, while the third and fifth statements are incorrect.

The scale factor of 0.75, being less than 1, suggests that the vertices of the image are closer to the origin compared to those of the pre-image.

Hence, the fourth statement "The vertices of the image are nearer to the origin compared to the pre-image" is indeed correct.

7 0
2 months ago
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When jumping, a flea rapidly extends its legs, reaching a takeoff speed of 1.0 m/s over a distance of 0.50 mm . part a what is t
zzz [12365]

The flea experiences an acceleration of 1,000 m/s².

Detailed explanation

This scenario involves motion with constant acceleration.

The relevant variables include the following.

\boxed{u \ or \ v_i = initial \ velocity}

\boxed{u \ or \ v_t \ or \ v_i = terminal \ or \ final \ velocity}

\boxed{a = acceleration \ (constant)}

\boxed{d = distance \ travelled}

We know the flea attains a takeoff velocity of 1.0 m/s over a distance of 0.50 mm.

The flea starts from rest, so the initial velocity is zero. The question asks for the flea's acceleration during leg extension.

The equation we apply is:

\boxed{ \ v^2 = u^2 + 2ad \ }

  • a = acceleration (m/s²)
  • u = initial speed = 0 m/s
  • v = takeoff velocity = 1.0 m/s
  • d = displacement = 0.50 mm

First, convert 0.50 mm to meters: \boxed{0.50 \ mm = 0.50 \times 10^{-3} \ m = 5.0 \times 10^{-4} \ m}

Solution steps:

Rearrange the formula to isolate acceleration (a).

\boxed{ \ v^2 = u^2 + 2ad \ }

\boxed{ \ v^2 - u^2 = 2ad \ }

\boxed{ \ 2ad = v^2 - u^2 \ }

\boxed{ \ a = \frac{v^2 - u^2}{2d} \ }

Insert the given values into the rearranged equation.

\boxed{ \ a = \frac{(1.0)^2 - (0)^2}{2(5.0 \times 10^{-4})} \ }

\boxed{ \ a = \frac{1}{10 \times 10^{-4}} \ }

\boxed{ \ a = \frac{1}{1 \times 10^{-3}} \ }

\boxed{ \ a = 1 \times 10^{3}\ = 1,000 \ m/s^2 \ }

This yields the flea's acceleration as 1,000 m/s².

Additional resources

  1. Scientific notation: brainly.com/question/7263463
  2. Determining substance mass: brainly.com/question/4053884
  3. Conversion into cubic units: brainly.com/question/1446243

Keywords: flea, jumping, leg extension, takeoff velocity, initial speed, displacement, acceleration, constant acceleration, unit conversion

5 0
3 months ago
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"There are 3 teams of 18 employees working today. Company policy says that we need to have 1 supervisor for every 8 employees on
tester [12383]
They require six supervisors.
8 0
3 months ago
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The number of rainbow smelt in Lake Michigan had an average rate of change of −19.76 per year between 1990 and 2000. The bloater
Zina [12379]

Answer:

x = 11.33 years

Step-by-step explanation:

The equation for rainbow smelt is Y1 = −19.76x + 227

For bloater fish, the equation is Y2 = –92.57x + 1052

To find where these populations are equal:

–19.76x + 227 = –92.57x + 1052

Combine like terms:

-19.76x + 92.57x = 1052 - 227

72.81x = 825

Now divide by 72.81:

x = 825 / 72.81

Thus,

x = 11.33 years

6 0
2 months ago
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