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frosja888
7 days ago
11

N the diagram, the ratios of two pairs of corresponding sides are equal.

Mathematics
2 answers:
babunello [8.4K]7 days ago
4 0

Answer:

Correct answer: A

Step-by-step explanation:

Leona [9.2K]7 days ago
3 0

Answer:

\angle N\cong \angle Z

Step-by-step explanation:

Given:

In ΔLMN and ΔXYZ, MN=3\,,\,LN=2\,,\,YZ=9\,,\,XZ=6

To find: criteria that needs to be shown to prove ΔLMN \sim ΔXYZ using SAS similarity theorem

Solution:

According to SAS Similarity Theorem, if two sides in one triangle are proportional to two sides in another triangle and the included angle between the sides are congruent, then the two triangles are said to be similar.

In ΔLMN and ΔXYZ,

\frac{LN}{XZ}=\frac{2}{6}=\frac{1}{3}\\\frac{MN}{YZ}=\frac{3}{9}=\frac{1}{3}\\\therefore \frac{LN}{XZ}=\frac{MN}{YZ}

So, ΔLMN \sim ΔXYZ by SAS similarity theorem if \angle N\cong \angle Z

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AnnZ [9099]

Answer:

The correct selection is 1.

Step-by-step explanation:

The histogram indicates that

In the 5-10 age group, there are 7 students.

In the 11-13 age group, 5 students are represented.

In the 14-18 age category, 4 students are included.

This implies that the ages of 7 students fall within the 5-10 range, 5 students within the 11-13 range, and 4 students within the 14-18 range.

The total count in the dataset is 7+5+4=16

In options 3 and 4, the counts in the datasets are fewer than 16. Hence, options 3 and 4 are invalid.

Option 2 exclusively contains data within the 5-10 range, making it incorrect as well.

In option 1,

Class intervals      elements           frequency

5-10                    5,6,7,8,9,10,10           7

11-13                  11,11,12,12,13            5

14-18                    14,14,15,16              4

Based on the above table, we can determine that data set 1 is represented in the provided histogram.

Thus, the answer is option 1.

4 0
8 days ago
Read 2 more answers
Helen draws a random circle.
Leona [9271]

Answer:

Upper limit: 3.116

Lower limit: 3.125

Step-by-step breakdown:

The random circle drawn by Hellen has a circumference of C=405 mm, measured to 3 significant figures, leading to a diameter, d, of 130 mm, accurate to 2 significant figures.

We utilize the formula

\pi = \frac{C}{d}

Substituting in the figures provides:

\pi = \frac{405}{130}

\pi = 3.11538461538

Consequently, Hellen’s value for π is recorded as 3.115 to three decimal places.

To find both limits, we divide the specified level of precision by two.

\frac{0.001}{2} = 0.0005

This figure is then added to the rounded number to determine the upper limit:

3.115+0.0005=3.1155

The lower limit calculates as 3.115-0.0005=3.1145

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17 days ago
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A normal distribution is most effective when dealing with a substantial sample size. Without knowing how many containers there are, it's challenging to determine if it’s suitable for modeling the container weights.
4 0
13 days ago
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A balance scale was in perfect balance when Jane placed a box of candy on one pane of the balance and 3/4 of the same sized cand
AnnZ [9099]

Answer:

Step-by-step explanation:

I'm fairly certain that addition is needed here.

When we combine two fractions like 3/4 + 3/4, we ensure that the denominators (the bottom parts) are identical before simply adding the numerators (the top parts).

In this case, the denominators match, so we straightforwardly combine 3+3 to get 6/4. The denominator remains the same.

               answer:

                      3/4 + 3/4    =   6/4

Hope this helps!

5 0
1 month ago
A taxi charges a flat rate of $3.00, plus an additional $0.50 per mile. Carl will only take the taxi home if the cost is under $
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27 days ago
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