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polet
2 months ago
10

A cylindrical tank has a radius of 2 m and a height of 9 m. The tank is filled with water. Find the work needed to pump the top

3 m of water out the top of the tank. (Use 9.8 m/s2 for g and the fact that the density of water is 1000 kg/m3.)
Mathematics
1 answer:
Leona [12.6K]2 months ago
8 0
The required work to pump water is 3,325,140 Joules. Step-by-step explanation: Work done by the pump is calculated by multiplying the force exerted on the pump by the distance the water is moved. Force equates to mass multiplied by gravitational acceleration. Consequently, Force = (water density × tank volume) × gravitational acceleration, leading to F = ρVg. Therefore, Work done = (ρVg) * d. Given the values of ρ = 1000 kg/m³, g = 9.8 m/s², d = 3 m, we compute the work done: Work = 1000 * 113.10 * 9.8 * 3 = 3,325,140 Joules.
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