There are 10 boys and 12 girls in the tennis club. The coach wants to select two players to practice first. Which statements are
true? Check all that apply. There is approximately a 27 percent likelihood that one boy and one girl will be chosen to practice first.
There is approximately a 52 percent likelihood that one boy and one girl will be chosen to practice first.
There is approximately a 19 percent likelihood that two boys will be chosen to practice first.
There is approximately a 19 percent likelihood that two girls will be chosen to practice first.
There is approximately a 29 percent likelihood that two girls will be chosen to practice first.
Given there are 22 participants total, the possible pairs chosen for the initial practice session are calculated as 22C2 = 231 . The probability of selecting one individual from each gender can be determined using the following calculation: (10C1)x(12C1) / 231 = 40/77 . Approximately 52% represents the probability in percentage form, so the correct answer is the first option.
The second, third, and fifth options are the accurate selections. Choosing one girl and one boy results in (12C1*10C1)/22C2= approximately 52% Selecting two boys gives 10C2/22C2= roughly 19% And for two girls, it equals 12C2/22C2= near 29%
