Answer:
The composite function;
f(g(x) = 2x^2 + 15
Step-by-step explanation:
Given f(x) = 2x + 1 and g(x) = x^2 + 7;
we are tasked with calculating f(g(x))
This represents a composite function where we substitute g(x) into f(x)
Consequently, we find
f(g(x)) = 2(x^2 + 7) + 1
f(g(x)) = 2x^2 + 14 + 1
f(g(x)) = 2x^2 + 15
Additional 300 grams of flour will be required.
Answer:
There is a probability of 24.51% that the weight of a bag exceeds the maximum permitted weight of 50 pounds.
Step-by-step explanation:
Problems dealing with normally distributed samples can be addressed using the z-score formula.
For a set with the mean
and a standard deviation
, the z-score for a measure X is calculated by

Once the Z-score is determined, we consult the z-score table to find the related p-value for this score. The p-value signifies the likelihood that the measured value is less than X. Since all probabilities total 1, calculating 1 minus the p-value gives us the probability that the measure exceeds X.
For this case
Imagine the weights of passenger bags are normally distributed with a mean of 47.88 pounds and a standard deviation of 3.09 pounds, thus 
What probability exists that a bag’s weight will surpass the maximum allowable of 50 pounds?
That translates to 
Thus



has a p-value of 0.7549.
<pthis indicates="" that="" src="https://tex.z-dn.net/?f=P%28X%20%5Cleq%2050%29%20%3D%200.7549" id="TexFormula10" title="P(X \leq 50) = 0.7549" alt="P(X \leq 50) = 0.7549" align="absmiddle" class="latex-formula">.
Additionally, we have that


There is a probability of 24.51% that the weight of a bag will exceed the maximum allowable weight of 50 pounds.
</pthis>
Answer:
150 short-sleeve shirts were ordered
100 long-sleeve shirts were ordered
Conclusion:
Please refer to the explanation provided.
Detailed explanation:
Starting with these facts:
Total revenue = $250
Fee charged = $70 per car
Tips received = $50
Equation 1 representing the above:
(Fee per car × number of cars) + tips = total revenue
Let the number of cars be c.
Thus, we have:
$70c + $50 = $250
Part B:
Total revenue = $250
Fee charged = $75 per car
Tips received = $35
Supplies cost per car washed = $5
Equation 2:
(Fee per car × number of cars) + tips - (supplies cost × number of cars) = total revenue
$75c + $35 - $5c = $250
$70c + $35 = $250
Part C:
Equation 1 does not factor in costs associated with washing the car, while equation 2 does incorporate costs, which are deducted from the amount charged per car. Additionally, tips in equation 1 total $50 compared to a $35 fee in equation 2.