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tino4ka555
2 months ago
9

A dataset has 1000 records and 50 variables with 5% of the values missing, spread randomly throughout the records and variables.

an analyst decides to remove records that have missing values. about how many records would you expect would be removed?
Mathematics
1 answer:
tester [12.3K]2 months ago
8 0
Answer: 50

Explanation:

Given that 5% of the values are absent, the anticipated number of records to be deleted corresponds to the expected value regarding the records with missing values, which has a probability of 0.05.

Thus, the expected number of records to be removed is calculated using

Expected Value = (number of records)(probability of missing value)
= (1000)(0.05)
Expected Value = 50  
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11 Points Estimate the average by first rounding to the nearest 1,000: 1,000 2,300 2,600
Zina [12379]

Response:

Average = 2000

Step-by-step breakdown:

The numbers provided are:

1,000 2,300 2,600

To calculate the average:

Initially, round each number to the nearest 1000, then determine the average.

Solution:

1000 is already rounded, so it stays the same.

To round to the nearest thousand, check the hundred's digit.

  • If the hundred’s digit exceeds 5, the thousand’s digit increases by 1, and the hundred’s digit is set to 0.
  • If it’s less than 5, the thousand’s digit remains the same, changing the hundred’s digit to 0.

Thus, 2300 rounds to 2000.

and 2600 rounds to 3000.

Consequently, the numbers for averaging are 1000, 2000, 3000.

The formula for average is as follows:

Average = \dfrac{\text{Sum of all numbers}}{\text{Count of numbers}}

upon applying the formula:

Average = \dfrac{1000+2000+3000}{3}\\\Rightarrow Average = \dfrac{6000}{3}\\\Rightarrow \bold{Average = 2000}

So, the average after rounding to the nearest 1000 is 2000.

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1 month ago
A train travels train travels 288 kilometre at a uniform speed. If the speed had been 4 kilometre per hour more it would have ta
PIT_PIT [12445]

Answer:

Let the train's speed be denoted as x km/h.

Scenario 1:

Distance = 288 km

Speed = x km/h

Time = Distance divided by Speed

= 288/x hours

Scenario 2:

Distance = 288 km

Speed = (x + 4) km/h

Time = 288/(x + 4) hours

As 288/x is greater than 288/(x + 4)

288/x - 288/(x + 4) = 1

288[1/x - 1/(x + 4)] = 1

[x + 4 - x] / [x(x + 4)] = 1/288

[4 / (x^2 + 4x)] = 1/288

x² + 4x = 1152

x² + 4x - 1152 = 0

x² + 36x - 32x - 1152 = 0

x(x + 36) - 32(x + 36) = 0

(x + 36)(x - 32) = 0

x + 36 = 0, x - 32 = 0

x = -36, x = 32

x = -36 is not valid as speed cannot be negative.

Conclusively, the train's speed = 32 km/h

4 0
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The graph indicates that x never goes below 0. This means the point (-1,0) is not included in the graph. Therefore, D is the only valid option.

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