Answer:
25 one-dollar bills, 13 five-dollar bills, and 12 ten-dollar bills.
Step-by-step explanation:
The equations that can be formed are:
x+y+z=50 (1)
x+5y+10z=210 (2)
x= 2y-1 (3)
where x = number of one-dollar bills,[tag_20] y = number of five-dollar bills,
z = number of ten-dollar bills
Substituting (3) into (1) and (2) gives:[
2y-1+y+z= 50
3y+z=51
2y-1+5y+10z= 210
7y+10z=211
You will then derive the following equations:
3y+z=51 (4)
7y+10z=211 (5)
Next, isolate z using (4) and substitute it into (5):
z= 51-3y
7y+10(51-3y)=211
7y+510-30y=211
-23y=-299
y= 13
After substituting the value of y into z= 51-3y, we find:
z=51-3(13)= 51-39= 12
Now, replace y's value in (3):
x=2(13)-1= 26-1= 25
Thus, the final result indicates there are 25 one-dollar bills, 13 five-dollar bills, and 12 ten-dollar bills.
