Answer:
Pseudo CODE
a)
n= Input “Enter 5 integer values”
b)
sum=0.0
For loop with i ranging from 0 to 5
Inside loop sum=n[i]+sum
Outside loop avg=sum/5
Print avg
c)
small=n[0] # assume initial number is the smallest
large=n[0] # assume initial number is the largest
For loop with i ranging from 0 to 5
Inside loop if n[i]<small # check if current number is smaller than small
Inside if Then small=n[i]
Inside loop if n[i]>large # check if current number is larger than large
Inside if then large=n[i]
Print small
Print large
d)
print avg
print small
print large
Complete Question:
Remember that in the CSMA/CD protocol, after a collision, the adapter pauses for K. 512 bit times, where K is randomly chosen. a. For the first collision, if K=100, what is the waiting duration before sensing the channel again for a 1 Mbps broadcast channel? And for a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
With K set at 100, the duration the adapter must wait after detecting a collision is calculated using the following formula:
The bit time is determined by the inverse of the channel's bandwidth, expressed in bits per second. Therefore, for the instances mentioned in the question, we get:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
Given that Sophie frequently commits numerous spelling and grammar mistakes in her document, it would be beneficial for her to utilize a function provided by Microsoft Word that assists her in recognizing her errors, which is what (D) Explain accomplishes.
Explain would indicate to Sophie the portions of her sentences that are incorrect, the words that were mistyped, and offer suggestions for better phrasing to prevent fragmented sentences.
Answer:
Explanation:
For this illustration, I'll provide a Python program step-by-step:
- We define four variables regarding our zoo, including the zoo count and the average.
- The average is calculated by summing the totals of owls and dividing by the number of zoos.
- Finally, we display the value stored in avg_owls.
num_owls_zoo1 = 1
num_owls_zoo2 = 2
num_owls_zoo3 = 3
num_owls_zoo4 = 4
zoos = 4
avg_owls = 0.0
avg_owls=(num_owls_zoo1+num_owls_zoo2+num_owls_zoo3+num_owls_zoo4)/zoos
print('Average owls per zoo:', int(avg_owls))
