Answer:
Noah’s average: 87
Noah’s median: 85.5
Noah’s mode: 85
Gabriel’s average: 87.17
Gabriel’s median: 86
Gabriel’s mode: 86
Step-by-step explanation:
The mean is calculated as (total/number of items), or the average.
The median refers to the central value in a dataset.
The mode represents the number that appears most frequently.
Answer:
(A) 0.15625
(B) 0.1875
(C) Cannot be determined
Step-by-step explanation:
The time it takes for a student to finish a statistics quiz is uniformly distributed between 32 and 64 minutes.
Let's denote X as the duration needed for the student to complete the statistics quiz
Thus, X ~ U(32, 64)
The probability density function (PDF) for a uniform distribution is expressed as;
f(X) =
, a < X < b where a = 32 and b = 64
The cumulative distribution function (CDF) is given by P(X <= x) =
(A) The probability of a student taking longer than 59 minutes to complete the quiz = P(X > 59)
P(X > 59) = 1 - P(X <= 59) = 1 -
= 1 -
=
= 0.15625
(B) The probability that a student completes the quiz between 37 and 43 minutes = P(37 <= X <= 43) = P(X <= 43) - P(X < 37)
P(X <= 43) =
=
= 0.34375
P(X < 37) =
=
= 0.15625
P(37 <= X <= 43) = 0.34375 - 0.15625 = 0.1875
(C) The probability that a student takes exactly 44.74 minutes to complete the quiz
= P(X = 44.74)
This probability cannot be calculated as it is a continuous distribution, which doesn't provide probabilities for specific points.
2x^2 - y = -5
x + y = 8
----------------adding gives us
2x^2 + x = 3 <==
** It's important to note that 2x^2 and x cannot be combined, because they are not like terms.
Answer:
box 1: monomial
box 2: binomial
Step-by-step explanation:
rationale: The volume of Box 1 is represented by a monomial multiplied by another monomial, resulting in a monomial.
Conversely, the volume of Box 2 is represented by a monomial multiplied by a binomial, producing a binomial.
Answer:
Step-by-step explanation:
It has been established that the count of drivers traveling between a specific origin and destination in a certain time frame follows a Poisson distribution with a mean μ = 20 (as indicated in the article "Dynamic Ride Sharing: Theory and Practice"†).
a) 
b) 
c) 
d) 2 standard deviations = 2(20) = 40
Thus, this means the range for 2 standard deviations is
20-40, 20+40
which equates to (0,60)
