Jala put $600 in an interest bearing account with a annual compound interest rate of 5%. Jala determined that after seven years,

The tension does not approach infinity.
<span>Let's analyze free body diagrams (FBDs) for each mass, considering the direction of motion of m₁ as positive.

For m₁: m₁*g - T = m₁*a

For m₂: T - m₂*g = m₂*a

Assuming a massless cord and pulley without friction, the accelerations are the same.

From the second equation: a = (T - m₂*g) / m₂

Substitute into the first:
m₁*g - T = m₁ * [(T - m₂*g) / m₂]
Rearranging:
m₁*g - T = (m₁*T)/m₂ - m₁*g
2*m₁*g = T * (1 + m₁/m₂)
2*m₁*m₂*g = T * (m₂ + m₁)
T = (2*m₁*m₂*g) / (m₂ + m₁)
Taking the limit as m₁ approaches infinity:
T = 2*m₂*g

This aligns with intuition since the greatest acceleration m₁ can have is -g. The cord then accelerates m₂ upward at g while gravity acts downward, leading to a maximum upward acceleration of 2*g for m₁.</span>

Answer:

________{0.50 if x < 3

________{1.00 if 3 ≤ x < 6

f(x) = ____{1.50 if 6 ≤ x < 9

________{2.00 if 9 ≤ x < 12

Step-by-step explanation:

Based on the details provided:

Employees with less than 3 years receive an increase of $0.50 hourly

Employees with at least 3 years but under 6 years receive $1.00 increase hourly

Employees with a minimum of 6 years and less than 9 get $1.50 increase hourly

Employees with at least 9 years but below 12 years receive $2.00 increase hourly

This information can be expressed as a piecewise function:

________{0.50 if x < 3

________{1.00 if 3 ≤ x < 6

f(x) = ____{1.50 if 6 ≤ x < 9

________{2.00 if 9 ≤ x < 12

The conditions are outlined in the piecewise function above with x indicating the number of years employed.

Explanation:

Hello! Please remember to formulate complete questions to receive accurate answers. I will assume that the depicted function derives from:

This describes the equation of a parabola that opens upwards, with its vertex positioned at:

The graph below illustrates this function. What is true about the graphed function f(x)?

• It is accurate that the domain consists of all real numbers, as this is a polynomial function.

• It is also correct that the range includes all real numbers where y ≥ 5

• It is indeed true that this parabola opens upwards

• It is valid to say it does not intersect the x-axis

Answer:

C. The mean daily salary is not above $350 per day

Step-by-step explanation:

The calculation is displayed below:

Y = a + bX

where,

Y = earnings of a randomly chosen agent

a = $150

b = $50

X = number of loans closed

Now

E(x) = (1 × 0.05) + (2 × 0.10) + (3 × 0.22) + (4 × 0.30) + (5 × 0.18) + (6 × 0.12) + (7 × 0.03)

= 3.94

Consequently,

E(y) = $150 + ($50 × 3.94)

= $347

therefore, option C is incorrect

Answer:

The hourly rate for lectures is $7.33

Step-by-step explanation:

* Let's break down how to tackle the problem.

- For the level 3 course, examination hours are priced at double that of workshop hours.

- Workshop hours cost twice the rate of lecture hours.

- The total includes examination, workshop, and lecture hours.

- Examination lasts 3 hours, workshops 24 hours, and lectures 12 hours.

* Let’s denote the cost of lecture hours as $x per hour.

∴ The lectures cost $x per hour.

∵ Workshop charge is twice that of lectures

∴ Workshop hours cost 2(x) = 2x per hour.

∵ Examination fees are double that of workshop hours

∵ The workshop cost is 2x

∴ Examination fees are 2(2x) = 4x per hour.

- Combining costs for level 3 gives us the total of lecture, workshop, and examination hours.

∵ 12 hours for lectures

∵ 24 hours for workshops

∵ 3 hours for examinations

∵ Thus the total cost for level 3 = 12(x) + 24(2x) + 3(4x).

∴ Total cost for level 3 = 12x + 48x + 12x.

∵ Therefore, total cost = $528.

∴ 12x + 48x + 12x = 528.

∴ 72x = 528; hence we divide both sides by 72.

∴ x = 7.33.

∵ x represents the cost of lecture hours per hour.

∴ Therefore, the hourly price for lectures is $7.33.