In cell F15, insert a function that will automatically display the word Discontinue if the value in cell D15 is less than 1500,

Response:

John Blankenbaker

Reasoning:

Answer:

Below is the JAVA program:

import java.util.Scanner;   //to take input from user

public class Main {  //name of the class

  public static void main(String[] args) {  //beginning of main method

      Scanner input = new Scanner(System.in);  //creates Scanner instance

      int integer = input.nextInt();  //defines and collects an integer for the number of words

      String stringArray[] = new String[integer]; //initializes an array to hold strings

      for (int i = 0; i < integer; i++) {  //iterates through the array

          stringArray[i] = input.next();         }  //collects strings

      int frequency[] = new int[integer];  //creates an array for holding frequencies

      int count;         //initializes variable to calculate frequency of each word

      for (int i = 0; i < frequency.length; i++) {  //iterates through frequency array

          count = 0;  //sets count to zero

          for (int j = 0; j < frequency.length; j++) {  //iterates through array

              if (stringArray[i].equals(stringArray[j])) {  //checks if element at ith index matches jth index

                  count++;                 }            }  //increments count

          frequency[i] = count;      }  //stores count in the frequency array

      for (int i = 0; i < stringArray.length; i++) {  //iterates through the string array

          System.out.println(stringArray[i] + " " + frequency[i]);         }    }    } //displays each word and its frequency

Explanation:

To illustrate the program, consider:

let integer = 3

for (int i = 0; i < integer; i++) is used to input strings into stringArray.

On the first pass:

i = 0

0<3

stringArray[i] = input.next(); takes a word and saves it to the ith index of stringArray. For example, if the user types "hey", it will be in stringArray[0].

Then, i increments to i = 1

On the second pass:

i = 1

1<3

stringArray[i] = input.next(); takes another word and assigns it to stringArray[1]. If the user enters "hi", then hi will be in stringArray[1]

Next, i becomes i = 2

On the third pass:

i = 2

2<3

stringArray[i] = input.next(); captures a word and places it in stringArray[2]. If the user types "hi", it goes to stringArray[2]

Then, i increments to i = 3

The loop terminates since i<integers is false.

The next outer loop for (int i = 0; i < frequency.length; i++) and inner loop for (int j = 0; j < frequency.length; will check each word and if (stringArray[i].equals(stringArray[j])) identifies any duplicates. Words that repeat will have their count incremented and the frequency array will record these values. For example, hey appears once while hi shows up twice, thus resulting in the final outputs:

hey 1

hi 2

hi 2

The visual representation of the program and its outcome based on the example provided is attached.

Answer:

In Python:

total_coins = nickel_count + dime_count

Explanation:

The sums of nickel_count and dime_count are combined and assigned to total_coins.

Cheers.

Answer:

I am crafting a Python function:

def angry_file_finder(filename): #function definition, this function takes the file name as input

with open(filename, "r") as read: #the open() function is employed to access the file in read mode

lines = read.readlines() #readlines() yields a list of all lines in the file

for line in lines: #iterates through every line of the file

if not '!' in line: #checks if a line lacks an exclamation mark

return False # returns False if a line does not include an exclamation point

return True # returns true if an exclamation mark is present in the line

print(angry_file_finder("file.txt")) invokes the angry_file_finder function by supplying a text file name to it

Explanation:

The angry_file_finder function accepts a filename as its parameter. It opens this file in read mode utilizing the open() method with "r". Then it reads every line using the readline() function. The loop checks each line for the presence of the "!" character. If any line in the file lacks the "!" character, the function returns false; otherwise, it returns true.

There is a more efficient way to write this function without using the readlines() method.

def angry_file_finder(filename):

with open(filename, "r") as file:

for line in file:

if '!' not in line:

return False

return True

print(angry_file_finder("file.txt"))

The revised method opens the file in reading mode and directly uses a for-loop to traverse through each line to search for the "!" character. In the for-loop, the condition checks if "!" is absent from any line in the text file. If it is missing, the function returns False; otherwise, it returns True. This approach is more efficient for locating a character in a file.

Answer:

Clarification:

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