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irina1246
5 days ago
7

The following bar chart shows the number of different types of animals at two county fairs. Fair X had a total of 645 animals, a

nd fair Y had a total of 590 animals. Which of the following statements is supported by the bar chart?
Mathematics
1 answer:
Zina [9.1K]5 days ago
6 0

Answer:

The proportion of goats at fair Y exceeds that of goats at fair X.

Step-by-step explanation:

From the bar chart,  we see there were 100 goats at both fairs X and Y.

Calculating the percentage of goats at each fair we find:

Fair X = 100/645 * 100 = 15.5%

Fair Y = 100/590 * 100 = 16.9%

This indicates that fair Y had a higher percentage of goats compared to fair X.

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Which property does each equation demonstrate? x2 + 2x = 2x + x2 (3z4 + 2z3) – (2z4 + z3) = z4 + z3 (2x2 + 7x) + (2y2 + 6y) = (2
babunello [8423]

Response:

1. Closure

2. Distributive

3. Closure

Detailed explanation:

In this scenario, we are examining the properties that each equation demonstrates.

The first equation shows the closure property.

This indicates that whether we add in one direction or the other, the result remains unchanged. Therefore, we conclude that addition conforms to the closure property in this case.

The third equation also shows the closure property. Regardless of how we approach the addition for this equation, the outcome remains consistent.

The second equation displays the distributive property.

Each element within the parentheses is multiplied by the negative sign before we proceed with further calculations.

5 0
22 days ago
Mel slides down waterslide A, and Victor slides down waterslide B. After 2 seconds, Mel was 50 feet in the air, and after 5 seco
Leona [9271]
Mel descends 50-35=15 feet in 5-2=3 seconds. Thus, her descent rate is 15/3=5 ft/sec.
Victor descends 60-50=10 feet in 4-1=3 seconds. Hence, his descent rate is 10/3=3⅓ ft/sec. Mel is faster, traveling at 5 ft/sec.
7 0
4 days ago
Read 2 more answers
A man 50 years old has 8 sons born of equal intervals. The sum of the ages of the father and sons is 186. What is the age of the
babunello [8423]
<span>Denote x as the interval, then: 186 = 50 + 3 + (3+x) + (3+2x) + (3+3x) + (3+4x) + (3+5x) + (3+6x) + (3+7x) 186 = 74 + 28x x = 4 Age of the eldest son = 3+7x = 3+28 = 31.</span>
8 0
9 days ago
A local weather enthusiast wants to see if the last five summers have been warmer than normal for Eloy, Arizona. From the Nation
Leona [9271]
The average temperature for July over the past 30 years in Eloy and Arizona is 90°. The standard deviation is 2.1°. This implies that the temperature over these 30 years spans from 90° - 2.1° to 90° + 2.1°, which equals 87.9° to 90°. The average for the last five summers in Eloy and Arizona is 92°. To calculate the reduction, which is 2.5% from 92, we find that 89.70° is within the 87.9° to 90° range. Thus, it can be concluded that the two averages are likely identical.
5 0
4 days ago
Read 2 more answers
What is the logarithm of the equilibrium constant, log K, at 25°C of the voltaic cell constructed from the following two half-re
lawyer [9240]

Answer:

4.0921 reflects the logarithm of the equilibrium constant.

Step-by-step explanation:

Fe^{2+} (aq) +2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

Ag^+(aq) + e^-\rightarrow Ag(s); E° = 0.80 V

Iron has a negative reduction potential, indicating its tendency to lose electrons and undergo oxidation, and thus it will be at the anode.

E^{o}_{cell}=Reduction potential of cathode - Reduction potential of anode

E^{o}_{cell}=E^{o}_c-E^{o}_a

=0.80 V-(-0.41 V)=1.21 V

Fe^{2+} (aq) + 2e^{-}\rightarrow Fe(s); ​E​° = - 0.41 V

2Ag^+(aq) + 2e^-\rightarrow 2Ag(s); E° = 0.80 V

Net reaction: Fe(s)+2Ag^{+}\rightarrow Fe^{2+}+2Ag(s)

n = 2

To determine the equilibrium constant, we utilize the correlation with Gibbs free energy, as follows:

\Delta G^o=-nfE^o_{cell}

and,

\Delta G^o=-RT\ln K_{eq}

Aligning these two equations yields:

nfE^o_{cell}=RT\ln K_{eq}

where,

n = electrons transferred = 2

F = Faraday's constant = 96500 C

E^o_{cell} = standard electrode potential of the cell = 1.21 V

R = gas constant = 8.314 J/K.mol

T = reaction temperature = 25^oC=[273+25]=298K

Substituting values into the equation, we arrive at:

2\times 96500\times 1.21 V=8.314\times 298\times \ln K_{eq}

\ln K_{eq}=9.3478

\log K_{eq}=\frac{9.3478}{2.303}=4.0921

4.0921 represents the logarithm of the equilibrium constant.

7 0
19 days ago
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